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2 years ago

Simplify the complex number. (8i) (5) (-4-6i)

Mathematics

2 answers:

Marta_Voda [28]2 years ago

5 0

$(8i)(5i)(-4-6i)\\\\=40i^2(-4-6i)\\\\=-40(-4-6i)~~~;[i^2=-1]\\\\=160+240i$

r-ruslan [8.4K]2 years ago

3 0

Answer:

4th option

Step-by-step explanation:

noting that i² = - 1

(8i)(5i)(- 4 - 6i)

= 40i²(- 4 - 6i)

= 40(- 1)(- 4 - 6i)

= - 40(- 4 - 6i) ← distribute parenthesis by - 40

= 160 + 240i

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