These questions can be daunting at first, but they're pretty simple to solve.
First, we need to establish a common denominator. We have 2 / 3, 1 / 4, and
-4 / 3. The least common denominator we can get is by multiplying 4 and 3 together to get 12. So we will change the denominator as follows;
2 / 3, 1 / 4, -4 / 3 = 8 / 12, 3 / 12, -16 / 12
Now we can put these back into the equation.
8/12x + 3/12 = -16/12
8x + 3 = -16
It's simple math from here on out, but I'll show the process. What we can basically do now is take away the denominator because it doesn't matter now that it's common.
Subtract 3 from both sides. Now we have 8x = -19
Dividing by 8 on both sides of the equation will get you your answer.
x = -19/8
Hope this helps!
Answer:
2 sqrt(15)
Step-by-step explanation:
sqrt(60) = sqrt(4*15) = 2 sqrt(15)
Answer:
This idea of reflection correlating with a mirror image is similar in math.
This complete guide to reflecting over the x axis and reflecting over the y axis will provide a step-by-step tutorial on how to perform these translations.
First, let’s start with a reflection geometry definition
Math Definition: Reflection Over the X Axis
A reflection of a point, a line, or a figure in the X axis involved reflecting the image over the x axis to create a mirror image. In this case, the x axis would be called the axis of reflection.
Math Definition: Reflection Over the Y Axis
A reflection of a point, a line, or a figure in the Y axis involved reflecting the image over the Y axis to create a mirror image. In this case, theY axis would be called the axis of reflection.
What is the rule for a reflection across the X axis?
The rule for reflecting over the X axis is to negate the value of the y-coordinate of each point, but leave the x-value the same.
Answer:
- Exact distance = feet
- Approximate distance = 127.2792 feet.
===========================================================
Explanation:
The area of the square is 8100 square feet, abbreviated ft^2.
Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.
If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).
Use the pythagorean theorem to find the hypotenuse.
The distance from 1st to 3rd base is roughly 127.2792 feet.