Assume L=1.5W, where W=width, L= Length of the triangle.
Therefore,
Perimeter (P) = 2(W+L) = 2(W+1.5W) = 2(2.5W) = 5W=20 => W=20/5 = 4 in
Then, L=1.5W = 1.5*4 = 6 in
Area, A= L*W = 6*4 = 24 in^2
Answer:
The sum is 2. ...........
If you are factoring it you can factor it into (x+5)^2
√52-√13+√117
sqrt (4*13) - sqrt (13) + sqrt (13*9)
sqrt(4)sqrt(13) -sqrt(13)+sqrt(13)sqrt(9)
2sqrt(13) -sqrt(13)+3sqt(13)
sqrt(13)[2-1+3]
4sqrt(13)
Choice A