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3 years ago

(-5z)^3 using only positove exponents

Mathematics

1 answer:

Elena L [17]3 years ago

8 0

Answer:

Shown below

Step-by-step explanation:

First allocate the power of three to every number

$-5^{3} * z^{3}$ = $-125 * z^{3}$

not sure what you mean by positive exponents, the exponents already are positive. Maybe you mean positive exponents and integers?

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Rhombus EFGH is shown. What is the length of EF ? A. 3 B. 6 C. 8 D. 9

liubo4ka [24]

Answer:

Step-by-step explanation:

The diagonals of a rhombus bisect each other, thus

FJ = JH, that is

y + 5 = 4x ( subtract 5 from both sides )

y = 4x - 5 → (1)

In a rhombus all sides are congruent, thus

HG = EF, substitute values

3x + y = 2x + y + 2 ( subtract y from both sides )

3x = 2x + 2 ( subtract 2x from both sides )

x = 2

Substitute x = 2 into (1)

y = 4(2) - 5 = 8 - 5 = 3

Thus

EF = 2x + y + 2 = 2(2) + 3 + 2 = 4 + 3 + 2 = 9 → D

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3 years ago

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scoundrel [369]

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3 years ago

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aliina [53]

Mean 74
Median 73
Mode 72

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3 years ago

Which collection of three side lengths can be used to form a triangle?

LUCKY_DIMON [66]

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zheka24 [161]

Solution :

$n_1=178, \hat p_1 = 0.48$

$n_2=427, \hat p_2 = 0.38$

$\hat p_1=\frac{x_1}{n_1}$

$x_1=n_1 \hat p_1$

= 178 x 0.48

= 85.44

≈ 85

$x_2=n_2 \hat p_2$

= 427 x 0.38

= 162.26

≈ 162

a). Yes, the sample sizes are large enough to use the large sample confidence interval so as to estimate the difference in the population proportions.

Let $\hat p_1 = 0.48, \ \ \hat p_2 = 0.38, n_1 = 178 \ \ n_2 = 427$