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Dennis_Churaev [7]
3 years ago
12

EMERGENCY! DUE VERY SOON! HELP!

Mathematics
1 answer:
kakasveta [241]3 years ago
8 0

Answer:

458

Step-by-step explanation:

21*21.8 = 457.8

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4x-2=3x+4 solve this
Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

x=6

8 0
3 years ago
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Luke and isabella make scale drawings.The scale from isabella's drawing is 6 m to 3 cm. The height of the fountain in isabella's
den301095 [7]

Answer:

The answer is "2.5 \ cm"

Step-by-step explanation:

While Luke is 5m to 2cm in size, it implies that every 2cm to Luke's drawing is 5m in real life. That real pond width must therefore be 5 m, given the fountain's width is 2 cm. As shown in the illustration, the step size for IsabelLa from the illustration to real life is \frac{6}{3} =2, which makes it simple to multiply any measure in the cm of her illustration by 2 to accomplish the exact size in m. So, in another direction around, they just have to divide the value by 2, instead of the divide from reality for drawing. So if the actual worth is 5m, it ought to be \frac{5}{2} = 2.5 \ cm in its width.

7 0
2 years ago
The graph of a function f(x) passes through the following points: (0,0), (1, -2), (2,0) Which of the following could be f(x)?
Sveta_85 [38]

Answer:

f(x)= 2x^2-4x

Step-by-step explanation:

3 0
2 years ago
Given a table of values of a quadratic function, which of the following do you absolutely need in order to find its equation? *
nadya68 [22]

Answer:

The general form of a quadratic function is --> y = ax2 + bx + c

Since (0, -2) exists for the function, we can plug in those values:

-2 = a(0)2 + b(0) + c

-2 = 0 + 0 + c

-2 = c

So now our function so far is --> y = ax2 + bx - 2

We have two pairs of coordinates left: (-1, -8) and (3, -8).

First, plug in the first pair and simplify as much as you can:

-8 = a(-1)2 + b(-1) - 2

-8 = a - b - 2 ( add 2 to both sides )

-6 = a - b (stop here because we can't go further)

Second, plug in the second pair and simplify as much as you can:

-8 = a(3)2 + b(3) - 2

-8 = 9a + 3b - 2 ( add 2 to both sides )

-6 = 9a + 3b (stop here because we can't go further)

Now we have these two equations left:

a - b = -6

9a + 3b = -6

Now we solve for a and b using systems of equations, using one of three ways:

substitution

elimination

graphing (not my favorite, but it is doable)

Using substitution:

a - b = -6 can be rewritten as a = b - 6

plug into the second equation and solve for b

9(b - 6) + 3b = -6 (distribute the 9)

9b - 54 + 3b = -6 (combine all of the b's)

12b - 54 = -6 (add 54 to both sides)

12b = 48 (divide by 12 on both sides to isolate b)

b = 4

plug b into one of the original two equations

a - 4 = -6 (add 4 to both sides)

a = -2

The quadratic equation for this table is y = -2x2 + 4b - 2

6 0
2 years ago
Solve 4 over x minus 4 equals the quantity of x over x minus 4, minus four thirds for x and determine if the solution is extrane
Vinil7 [7]
I'm thinking this is what the problem looks like: \frac{4}{x-4}= \frac{x}{x-4}- \frac{4}{3}.  The first thing to do is to move the \frac{x}{x-4} over to the other side because it has a common denominator with the other side.  Doing that and at the same time combining them over their common denominator looks like this: \frac{4-x}{x-4}= -\frac{4}{3}.  The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4).  Distributing through the parenthesis is 12 - 3x = -4x + 16.  Solving for x gives us x = 4.  Of course when we sub a 4 back in for x we get real problems, don't we?  Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.
6 0
3 years ago
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