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vova2212 [387]
2 years ago
8

Work out: 2/3p - 3/4 = 0.2

Mathematics
2 answers:
weqwewe [10]2 years ago
7 0

Answer:

2/3p - 3/4 = 2/10

2/3p = 38/40

p = 57/40 = 1 17/40

Step-by-step explanation:

sergij07 [2.7K]2 years ago
3 0

Answer:

p=7/5

Step-by-step explanation:

2/3p-3/4=2/10

2/3p-3/4=1/5

40/60p-45/60= 12/60

40/60p=12/60+45/60

40/60p=56/60

p=(56/60)/(40/60)

p=(56/60)×(60/40)

p= 7/5

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If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t
Sergio039 [100]

From the given information we can write the equation:

-16t^2 +96t + 4 = 112

-16t^2 + 96t + 4 - 112 = 0

-16t^2 + 96t - 108 = 0

simplify, change the signs, divide by -4

4t^2 - 24t + 27 = 0


You can use the qudratic formula but this will factor to

(2t-3)(2t-9) = 0

Two solutions

t = 3/2

t = 1.5 seconds at 112 ft on the way up

and

t = 9/2

t = 4.5 seconds at 112 ft on the way back down

Graphically, (green line is 112 ft)


5 0
3 years ago
Find the total surface area of this triangular prism
FinnZ [79.3K]

Answer:

976 cm^2.

Step-by-step explanation:

The surface area = 2 * area of the triangular side + 2 * area of the rectangular sides + area of the rectangular base.

= 2 + 1/2 * 24 * 14 + 2 * 25 * 10 + 14*10

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= 976 cm^2.

5 0
3 years ago
There are 20 packages of beef in a restaurant freezer. The average weight of 14 of the packages is 2 lb. The remaining packages
Shtirlitz [24]
I belive that the answer is about 180 lb.
3 0
3 years ago
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How many posts does it take to support a fence around a square field measuring 100 feet on a side if posts are placed every 10 f
elena-14-01-66 [18.8K]

Answer:

10 Posts

Step-by-step explanation:

100ft. / 10ft.

it's is kind of simple

3 0
3 years ago
What is 16% of 25?<br> a. 64<br> b. 16<br> c. 6<br> d. 4
valentina_108 [34]
If you would like to know what is 16% of 25, you can calculate this using the following steps:

16% of 25 = 16% * 25 = 16/100 * 25 = 4

Result: 16% of 25 is 4, so the correct result would be d. 4.
3 0
3 years ago
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