Answer:
I think that it is D or B from my side
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
2 x minus y = negative 6 and 3 x minus y = negative 5
Step-by-step explanation:
y = 2(x+3) = 2x + 6 or 2x - y = -6
y = 5 + 3x or 3x - y = -5
Answer:
x=2°
Step-by-step explanation:
(5x+35)°=45° because they are alternative angle
5x+35°=45°
5x=45°-35°
5x=10°
x=10°/5
x=2°
3 days they with both have 4 dollars
