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2 years ago

Help! open the attachment below!

Mathematics

1 answer:

gregori [183]2 years ago

6 0

Answer:

yes it is

Step-by-step explanation:X=side lenghths 2/3

Y=perimeter 12/18

2 time 6=12 and 3 times 6=18 and it is paraticly telling you

2/6 and 3/6 i beleve i need a lil more info

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What is hs the answer to this question?<br><br> Y= 5x+5<br> Y - x=5

ANEK [815]

Y = 5x + 5
y - x = 5

You can use substitution to solve this system. Use y's expression (5x + 5) for y in the second equation to solve for x:

y - x = 5
5x + 5 + x = 5
6x + 5 = 5
6x = 0
x = 0

Substitute your value for x into one of the original equations to y:

y = 5x + 5
y = 5(0) + 5
y = 5

Finally, substitute both values into both original equations to check your work:

5 = 5(0) + 5 --> 5 = 5 <--True
5 - 0 = 5 --> 5 = 5 <--True

Answer:
x = 0
y = 5

3 0

2 years ago

Winnie has 7 trophies she wants to display in an array.How many different arrays are possible? Explain.

Rama09 [41]

5,040 I think because 7•6•5•4•3•2•1=5040

6 0

2 years ago

Read 2 more answers

What is the domain of function of f(x)=-2x+4x

dem82 [27]

Answer:

Domain= x∉Real numbers

Step-by-step explanation:

4 0

2 years ago

Find the values of x and y

zhuklara [117]

You can use a tangent:

$tangent=\dfrac{opposite}{adjacent}$

We have opposite = 17 and adjacent = x.

$\tan30^o=\dfrac{\sqrt3}{3}$

substitute:

$\dfrac{17}{x}=\dfrac{\sqrt3}{3}$ cross multiply

$x\sqrt3=(3)(17)$ multiply both sides by √3

$x(\sqrt3)(\sqrt3)=51\sqrt3$

$3x=51\sqrt3$ divide both sides by 3

$x=17\sqrt3$

Use the Pythagorean theorem:

$y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34$

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Other method.

$30^o-60^o-90^o$ triangle.

The sides are in the ratio $1:2:\sqrt3\to17:y:x$

Therefore

$17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3$

4 0

2 years ago

2/3 divided by 11/15

NNADVOKAT [17]

You need to implement the process of "flip-flop" and multiply which is where you flip the second fraction and multiply.

$\frac{2}{3}$ ÷ $\frac{11}{15}$ ⇒ $\frac{2}{3}$ × $\frac{15}{11}$

Now you multiply across. 2×15=30 and 3×11=33

So now it is $\frac{30}{33}$

-----------------------------------------------------------
To reduce to the lowest terms, find the GCF common factor

The GCF is 3

Divide both the numerator and denominator by 3

$\frac{30}{33}$ ÷ $\frac{3}{3}$ = $\frac{10}{11}$

Answer: $\frac{10}{11}$

7 0

2 years ago