I would probaly have to say $63
[tex]<span>1\dfrac{1}{7}=\dfrac{1\cdot7+1}{7}=\dfrac{8}{7}\\\\1\dfrac{1}{7}:\dfrac{1}{9}=\dfrac{8}{7}:\dfrac{1}{9}=\dfrac{8}{7}\cdot\dfrac{9}{1}=\dfrac{72}{7}[tex]
Answer: 1 1/7 : 1/9 = 72 : 7
</span>
Answer:
<h3>
</h3>
Step-by-step explanation:
Answer:
diameter = m - c
Step-by-step explanation:
In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).
The sum of the lengths of the tangents from points A and B on side "c" is ...
(b-r) +(a-r) = c
(a+b) -2r = c
Now, the problem statement defines the sum of side lengths as ...
a+b = m
and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...
m -d = c
m - c = d . . . . add d-c
The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.
I would use subsitution
y=x-7
sub x-7 for every x
5x+2(x-7)=14
5x+2x-14=14
add 14 to both sides
7x=28
divide both sides by 7
x=4
sub
y=x-7
y=4-7
y=-3
x=4
y=-3
(4,-3)
