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2 years ago

how long will it take 14 machines to complete the task, given that 8 machines can complete the same task in 7 days?

Mathematics

1 answer:

torisob [31]2 years ago

4 0

Answer:

4 days

Step-by-step explanation:

If 8 machines can complete a task in 7 days, how long will 14 machines take?

So, it is obvious that if the number of machines increases, the number of days taken to complete the task decreases; thus proving that this is an indirect / inverse proportion.

Let's take x as the number of days we need to find out.

8 machines : 7 days

14 machines : x days

14 × x = 8 × 7

14x = 56

x = $\frac{56}{14}$

x = 4

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3 years ago

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EXPLANATION:
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3 years ago

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Each day, Robin commutes to work by bike with probability 0.4 and by walking with probability 0.6. When biking to work injuries

kvasek [131]

Answer:

64.65% probability of at least one injury commuting to work in the next 20 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Each day:

Bikes to work with probability 0.4.

If he bikes to work, 0.1 injuries per year.

Walks to work with probability 0.6.

If he walks to work, 0.02 injuries per year.

20 years.

$\mu = 20*(0.4*0.1 + 0.6*0.02) = 1.04$

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-1.04}*1.04^{0}}{(0)!} = 0.3535
$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3535 = 0.6465$

64.65% probability of at least one injury commuting to work in the next 20 years

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2 years ago

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2 years ago

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Unit conversion
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3 years ago

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