Solution: We are given:
![\mu=100,\sigma=15](https://tex.z-dn.net/?f=%5Cmu%3D100%2C%5Csigma%3D15)
We have to find the amount of water that represents the top 97.5%.
We need to find the z value corresponding to probability to 0.975. Using the standard normal table, we have:
![z(0.975)=1.96](https://tex.z-dn.net/?f=z%280.975%29%3D1.96)
Now using the z score formula, we have:
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
![1.96=\frac{x-100}{15}](https://tex.z-dn.net/?f=1.96%3D%5Cfrac%7Bx-100%7D%7B15%7D)
![1.96 \times 15 = x-100](https://tex.z-dn.net/?f=1.96%20%5Ctimes%2015%20%3D%20x-100)
![29.4=x-100](https://tex.z-dn.net/?f=29.4%3Dx-100)
![x=100+29.4 = 129.4](https://tex.z-dn.net/?f=x%3D100%2B29.4%20%3D%20129.4)
Therefore, 129.4 ounces amount of water represents the top 97.5%
11.7cm= 117/10cm
and
15.4cm=154/10
area= length * breadth
= 117/10*154/10
= 18018/100
=180.18cm square
So remember that <u>domain is the list of x-values that are possible on a line.</u>
With this graph, it appears that the x values are infinite after 0, <u>which makes the answer B. x ≥ 0.</u>
Answer:
x=34
Step-by-step explanation:
Please, see the attached file.
Thanks.