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topjm [15]
3 years ago
7

two congruent isosley triangles are joined as shown to form a pallalelagram the lagest angle of the palololagram is 116Write 2 e

quationssolve them to find the value of a and b
Mathematics
1 answer:
Kipish [7]3 years ago
4 0

Answer:

Step-by-step explanation:

Given two congruent, isosceles triangles are joined, as shown, to form a parallelogram, the largest angle of the parallelogram is 116 degrees. Write two equations. Write them find the value of a and the value of b.

We know that the sum of all the internal angles is 360 degree. So the equation will be

4 a + 2b = 360

According to the question the largest internal angle of the parallelogram is 116 degree.                So a + b = 116

Now we have the two equations as  

4a + 2b = 360

a + b = 116

Multiply the second equation by 4 we get

4a + 2b = 360

4a + 4b = 464

    Or – 2b = - 104

   Or b = 52

Now a + b = 116

Or a + 52 = 116

Or a = 116 – 52

Or a = 64

Therefore the values of  a and b are 64 and 52 degrees

hope that help mark me brinilylist

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Complete the number sequence <br> 30,80,180,330
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Two companies, A and B, make express delivery for small-item packages in a city. Company A charges a flat fee of RM70 per packag
bazaltina [42]

Using the <u>normal probability distribution and the central limit theorem</u>, it is found that:

a) There is a 0.1922 = 19.22% probability that Company B would charge more than Company A to deliver a small-item package.

b) The mean amount charged is of RM 51.5, with a standard deviation of 21.35.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem:

  • When a <u>fixed constant k</u> multiplies a variable, the mean is k\mu and the standard deviation is k\sigma
  • When two normal variables are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question, b is needed to solve a, so I am going to place the solution to item b first.

Item b:

Flat fee of RM20(not considered for the standard deviation), plus a variable fee of RM3.5, hence:

\mu_B = 20 + 3.5(9) = 51.5

\sigma = 6.1(3.5) = 21.35

The mean amount charged is of RM 51.5, with a standard deviation of 21.35.

Item a:

This probability is P(B - A) > 0. For the distribution, we have that:

\mu_{B-A} = \mu_B - \mu_A = 51.5 - 70 = -18.5

Since A has a constant fee, it's standard deviation is 0, hence:

\sigma_{B-A} = \sqrt{\sigma_A^2 + \sigma_B^2} = \sqrt{21.35^2} = 21.35

The probability is <u>1 subtracted by the p-value of Z when X = 0</u>, so:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 + 18.5}{21.35}

Z = 0.87

Z = 0.87 has a p-value of 0.8078.

1 - 0.8078 = 0.1922.

0.1922 = 19.22% probability that Company B would charge more than Company A to deliver a small-item package.

A similar problem is given at brainly.com/question/25403659

3 0
3 years ago
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