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il63 [147K]
2 years ago
5

Fill in the blanks to complete the sentences about zero pairs.

Mathematics
1 answer:
Svetlanka [38]2 years ago
8 0
Zero pairs are generated by combining the EQUAL number of positive and negative numbers .

A zero pair could be -11 + 11
You might be interested in
1
Maslowich

(−0.0081p)(t)=(15000)(2.718282)

Step 1: Divide both sides by -0.0081t.

−0.0081pt

−0.0081t

=

40774.227427

−0.0081t

p=

−40774.227427

0.0081t

Answer:

p=

−40774.227427

0.0081t

5 0
2 years ago
Let X denote the data transfer time (ms) in a grid computing system (the time required for data transfer) between a "worker" com
My name is Ann [436]

Answer:

a. The value of alpha is 3.014 and the value of beta is 12.442

b. The probability that data transfer time exceeds 50ms is 0.238

c. The probability that data transfer time is between 50 and 75 ms is 0.176

Step-by-step explanation:

a. According to the given data we have that the mean and standard deviation of the random variable X are 37.5 ms and 21.6.

Therefore, E(X)=37.5 and V(X)=(21.6)∧2  

To calculate alpha we would have to use the following formula:

alpha=E(X)∧2/V(X)

alpha=(37.5)∧2/21.6∧2

alpha=1,406.25 /466.56

​alpha=3.014

To calculate beta we would have to use the following formula:

β=  V(X) ∧2/E(X)

β=(21.6)  ∧2/37.5

β=466.56 /37.5

β=12.442

b. E(X)=37.5 and V(X)=(21.6)∧2  

Therefore, P(X>50)=1−P(X≤50)

Hence, To calculate the probability that data transfer time exceeds 50ms we use the following formula:

P(X>50)=1−P(X≤50)

=1−0.762

=0.238

The probability that data transfer time exceeds 50ms is 0.238

c. E(X)=37.5 and V(X)=(21.6)∧2  

​Therefore, P(50<X<75)=P(X<75)−P(X<50)  

Hence, To calculate the probability that data transfer time is between 50 and 75 ms we use the following formula:

P(50<X<75)=P(X<75)−P(X<50)

=0.938−0.762

=0.176

​

The probability that data transfer time is between 50 and 75 ms is 0.176

6 0
3 years ago
Please help I only have a few minutes left
GalinKa [24]

Answer:

4 because that's where the lines intercept

6 0
3 years ago
A carton measures 3 feet by 2 feet by 2 feet. A machine can fill the carton with packing material in 3 seconds. How long would i
True [87]
1) we calculate the volume of the first carton:
volume=length x width x height
volume=3 ft * 2 ft * 2 ft=12 ft³

Therefore: 
A machine can fill 12 ft³ in 3 seconds.

2) we calculate the volume of the second carton. 
volume=length x width x heigth
volume=4 ft * 5 ft * 6 ft=120 ft³

3) we calculate the time that the machine needs for fill the second carton with packing material by the rule of three.

12 ft³---------------------3 seconds
120 ft³--------------------      x

x=(120 ft³ * 3 seconds) / 12 ft³=30 seconds.

answer: 30 seconds. 


5 0
3 years ago
write an equation for a line that is parallel to line that passes through the points (5,5),(-1,3) and contains the point (-6,-8)
dimaraw [331]
Since the two lines are parallel then they have the same slope which = 1/3

since the line passes through (-6 , -8)

y+8 = (1/3)(x+6)

3y + 24 = x + 6

x - 3y = 18 is the equation
8 0
3 years ago
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