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sergiy2304 [10]
3 years ago
9

Examine the expanded form. A ∙ a ∙ a ∙ a ∙ a ∙ a ∙ a Which is the expression in exponential form? 7a 7a a7 a 7.

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
7 0
A^7. "A" raised to the power of 7 would be the exponential form. hope this helps.
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Simplify 7 - 3x - 4 + x<br> helppppppppp will give brainiest if correct!!!
posledela

Answer:

-2x+3

Step-by-step explanation:

7-3x-4+x=-2x+3

8 0
4 years ago
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Multiply each pair of factors. Type the product in<br>the space provided<br>(6 + 3i)(6 - 3i) =​
anygoal [31]

\bf \stackrel{\textit{difference of squares}}{(6+3i)(6-3i)}\implies (6)^2-(3i)^2\implies \stackrel{\textit{recall }i^2=-1}{36-(3^2 i^2)}\implies 36-(9\cdot -1) \\\\\\ 36+9\implies 45

3 0
3 years ago
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In two months, Mica spent a total of $305.43 on groceries. She spent $213.20 in the first month. How much did she spent in the s
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Mica spent $92.23 in the second month
3 0
4 years ago
50 points!!! Please help!
omeli [17]

Each of the answers given at the right talks about the fourth month. So let's compare each of the fourth month's profits.


When the month t = 4 in Company B, the company made 10 hundred (or 1000) dollars in profits.


When the month t = 4 in Company A, we evaluate the function at t = 4. To do that we put t = 4 into the function.


P(4) = 1.8(1.4)⁴


P(4) = 6.91488


Thus the company made 691.488 dollars of profit. So during the 4th month, Company B made more than A.


Each of the answers also talks about year end profits, which would be after 12 months. The function for company B is linear whereas it is exponential for A. An exponential function will grow faster in A and have higher maximum values. We can conclude that year end profits for A will be higher.


We put the statements together - that B makes in the 4th month but at year's end A will make more.


Thus, the third box is the best answer.

5 0
4 years ago
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In how many ways can 4 light bulbs be selected from a batch of 43 lights bulbs to be tested for defects? Assume no light bulb wi
lesantik [10]

Answer:

There are 123,410 ways

Step-by-step explanation:

The number of ways or combinations in which we can select k elements from a group of n elements is given by:

\frac{n!}{k!(n-k)!}

In this case, we can replace n by 43 and k by 4, because we are going to select 4 light bulbs from a batch of 43 light bulbs.

So, the number of combinations is calculated as:

\frac{43!}{4!(43-4)!}=123,140

It means that there 123,410 ways to select 4 light bulbs from a batch of 43 lights bulbs to be tested for defects

6 0
3 years ago
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