You do 18×6 and you get 108 so the answer is 108in
Answer:
Pr(all will survive in one year) = 0.35 to 2 decimal places
Pr(at least 8 will survive) = 0.39 to 2 decimal places.
Step-by-step explanation:
Probability of a tree surviving one year is 0.9. While not surviving probability is 1 - 0.9 = 0.1
This is obtained from the 90℅ surviving rate for one year planted by the landscaping firm.
Probability that if 10 trees are planted, all will survive for one year is:
0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9 = 0.9^10 = 0.349
Probability that at least 8 will survive in one year can be expressed as
8 survived x 2 not survived +(or) 9 survived x 1 not survived +(or) 10 survived
= [(0.9^8)x(0.1^2) + (0.9^9)x(0.1^1) + (0.9^10)] = 0.391
Step-by-step explanation:
Answer:
No, because water temperature is confounded with brand of detergent.
Step-by-step explanation:
There is a very possible chance of allowing a third or confounding variable to have creepwd into the research. The aim was to investigate which of two detergents prevents color from fading. Hence, the test for both detergents should be carried out under the same research condition. However, with adoption of different water temperature for each of detergent A and B, there may be a relationship between fading and water temperature which is not what are trying to investigate. This difference in temperature will thus cause a spurious relationship in our research. Hence, water temperature has been confounded with detergent brand, making this experimental design a bad one.
The formula for the area of the shaded region in the figure.
x² = 4py is mathematically given as
<h3>What is the formula for the area of the shaded region in the figure?</h3>
Parameters
Generally, the equation for the Area is mathematically given as
![& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\](https://tex.z-dn.net/?f=%26%20A%3D2%20%5Cint_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%5Cleft%28h-%5Cfrac%7Bx%5E%7B2%7D%7D%7B4%20p%7D%5Cright%29%20d%20x%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%28h%20x-%5Cfrac%7Bx%5E%7B3%7D%7D%7B12%20p%7D%5Cright%5D_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%5B%5Cleft%5Bh%202%20%5Csqrt%7Bp%20h%7D-%5Cfrac%7B1%7D%7B12%20p%7D%20%5Ccdot%282%20%5Csqrt%7Bp%20h%7D%29%5E%7B3%7D-0%5Cright%5D%5Cright.%20%5C%5C)
![&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h](https://tex.z-dn.net/?f=%26A%3D2%5Cleft%5B2%20h%5E%7B3%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B8%28%5Csqrt%7Bp%7D%29%5E%7B3%7D%28%5Csqrt%7Bh%7D%29%5E%7B3%7D%7D%7B12%20p%7D-0%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%5Cleft%5B2%20h%5E%7Bk%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B2%7D%7B3%7D%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%20%5Ctimes%20%5Cfrac%7B4%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%7D%7B3%7D%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Ccdot%20%5Csqrt%7Bp%7D%20%5Ccdot%20%5Csqrt%7Bh%7D%20%5Ccdot%20h%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Csqrt%7Bp%20h%7D%20%5Ccdot%20h)
In conclusion, the equation for the Area is
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68 + 54 + 59 + 70 + 69 + 65 + 73 + 59 + 74 + 54 = 586 grams
586 grams/10 = 58.6 grams (if you round it, you will get 59 grams)
hope this helps!!
