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Tems11 [23]
3 years ago
15

you have 87,520 grams of a radioactive kind of lead. How much will be left after 108 minutes if its half-life is 27 minutes

Mathematics
2 answers:
solniwko [45]3 years ago
6 0

Answer:

The answer is 5470 grams of lead will be left.

Step-by-step explanation:

<h3><u>Given</u>: </h3>

The half life of lead is 27 minutes

Now,

108/27 = 4

Here, we get the value 4 so, we divide the amount of lead by 4². i.e., 16

Now,

87520/16 = 5470

Thus, After 108 minutes 5470 grams of lead will be left.

 

<u>-TheUnknownScientist</u><u> 72</u>

olasank [31]3 years ago
5 0

Answer:

5,470 mg

Step-by-step explanation:

108 minutes is 4 half-lives:

<u> Time</u>    <u>   Lead</u>

<u>  Min.</u> <u>mg Pb</u>

   0        87520

  27        43760

  54        21880

  81         10940

108           5470

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The monthly profit for a small company that makes long-sleeve T-shirts depends on the price per shirt. If the price is too high,
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Answer:

A. $18

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C. p\in (16,20)

Step-by-step explanation:

Function:

f(p) = -50p^2 + 1,800p - 16,000

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The price that generates the maximum profit is ate vertex of parabola. Find the coordinates of the vertex:

p_v=\dfrac{-b}{2a}=\dfrac{-1,800}{2\cdot (-50)}=\dfrac{1,800}{100}=18\\ \\f(p_v)=-50\cdot 18^2+1,800\cdot 18-16,000=200

The price that generates the maximum profit is $18

The maximum profit is $200

<u>Part C:</u>

The company breaks even when the profit is positive. From the graph of the function you can see that the graph of the function is over p-axis for all p\in (16,20), so the positive profit is for p\in (16,20)

In p=16 and p=20, the profit is 0 and when p<16 and p>20, there will be a loss.

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4 years ago
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Answer:

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