You fly a helicopter for 20 minutes that goes at a speed of 240 km per hour. How far did you go?

What is (-6-4)divided by(-5)=

lbvjy [14]

= -2? i dont really know either

8 0

3 years ago

Read 2 more answers

Please help with these math questions

anastassius [24]

4) x=16
Vertical angles have equal angles when two lines intersect, which they do in this case.
3x-3=2x+13
Solve for x:
x=16

5) 34 degrees
Lines AK and MJ bisect each other perpendicually, so <ADJ is 90 degrees.
4x+3x-8=90
7x-8=90
7x=98
x=14
<CDJ=3x-8
=3(14)-8
=34 degrees

Hope this helps :)

6 0

4 years ago

Paolo paid $ 28 $ 28 for a hat that was originally priced at $ 35 $ 35 . By what percent was the hat discounted?

devlian [24]

The original price of the hat is $35. Paolo paid $28 for the hat.

So discount for the hat is $(35-28) = $7

$7 is discounted from $35. We have to find the percentage of the discount.

To find the percentage we have to divide the discount amount by the original price and then have to multiply it by 100.

So the discount percentage =

((7/35)×100) %

We can simplify 7/35 by dividing 7 and 35 both by 7. So we will get 1/5 after simplifying.

((1/5) ×100) %

(100/5)% = 20%

So the hat was discounted by 20%.

5 0

3 years ago

The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a

AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

Let X = time for this event for boys in secondary school

SO, X ~ Normal( $\mu=460,\sigma^{2} =40^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 460 seconds

$\sigma$ = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;

P(X > x) = 0.10 {where x is the required time which boy need to beat}

P( $\frac{X-\mu}{\sigma}$ > $\frac{x-460}{40}$ ) = 0.10