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2 years ago

May I please receive help?

Mathematics

2 answers:

Lapatulllka [165]2 years ago

8 0

Are you looking for a acute angle?

ra1l [238]2 years ago

4 0

Answer:

Its right angel

Step-by-step explanation:

Sorry if m wrong

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Work out the area of the trapezium ABDE. B 9 cm 6 cm 8 cm →D E

Evgen [1.6K]

Answer:

Area of the trapezium ABDE = 30 cm²

Step-by-step explanation:

Area of a trapezium = $\frac{1}{2}(b_1+b_2)h$

Here, $b_1$ and $b_2$ are the parallel sides of the trapezium

h = Distance between the parallel sides

From the picture attached,

ΔCAE and ΔCBD are the similar triangles.

So by the property of similarity their sides will be proportional.

$\frac{AE}{BD}= \frac{CE}{CD}$

$\frac{9}{6}=\frac{CE}{8}$

CE = $\frac{9\times 8}{6}$

CE = 12 cm

Therefore, DE = CE - CD

DE = 12 - 8 = 4 cm

Now area of trapezium ABDE = $\frac{1}{2}(AE+BD)(DE)$

= $\frac{1}{2}(6+9)4$

= 30 cm²

Therefore, area of the trapezium ABDE = 30 cm²

8 0

3 years ago

Cual es el 15% de 36000?

zimovet [89]

15% = 15/100 = 0,15

36000•0,15=5400

4 0

3 years ago

Jessica is planning a trip to South Africa. The following table shows some of her planned expenses for this trip, and

Softa [21]

Answer:

C $973.39

Step-by-step explanation:

the answer is C on e2020

7 0

3 years ago

Evaluate the line integral c y3 ds, c.x = t3, y = t, 0 â‰¤ t â‰¤ 3

Temka [501]

$\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\int_{t=0}^{t=3}t^3\sqrt{1^2+(3t^2)^2}\,\mathrm dt=\int_0^3t^3\sqrt{1+9t^4}\,\mathrm dt$

Take $u=1+9t^4$ so that $\mathrm du=36t^3\,\mathrm dt$ . Then

$\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\frac1{36}\int_{u=1}^{u=730}\sqrt u\,\mathrm du=\frac{730^{3/2}-1}{54}$

7 0

3 years ago

Can yall help me with this i forgot how to do this!

ss7ja [257]

Ok so cut the circles into the bottom number! Then which ever is more filled out put a < to it!! Hope this helps tell me if you need more!

7 0

3 years ago

Read 2 more answers