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Scilla [17]
2 years ago
14

May I please receive help?

Mathematics
2 answers:
Lapatulllka [165]2 years ago
8 0

Are you looking for a acute angle?

ra1l [238]2 years ago
4 0

Answer:

Its right angel

Step-by-step explanation:

Sorry if m wrong

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Use the clustering estimation technique to find the approximate total in the following question.
Stolb23 [73]

Answer:

2530

Step-by-step explanation:

First Round each number to the nearest 10s

503 into 500

472 into 470

499 into 500

539 into 540

522 into 520

then add the numbers we made

500+470+500+540+520=2530

the real answer is 2535 so its close

4 0
3 years ago
Read 2 more answers
Please help me ASAPP
swat32
Answer:

I believe the answer is, A.

Explanation:

Ordered pairs are classified as a function when none of the x’s in the ordered pairs match.

Like in b, a pair has 3.
And in c, two pairs have 1 and 3.
7 0
3 years ago
A manufacturer finds that the revenue generated by selling x units of a certain commodity is given by the function R(x) = 60x −
bonufazy [111]
R(x) = 60x - 0.2x^2

The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150

Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
7 0
3 years ago
Read 2 more answers
Please answer accurately and show work if you can
scoundrel [369]

Answer:

A. a - 3 ≤ -5

Step-by-step explanation:

Move all terms with a to the right side of the inequality

7 0
3 years ago
John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart
Rina8888 [55]
<h2>Answer:</h2>

Probability=\frac{1}{24}

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is \frac{1}{24}</u></em>

3 0
3 years ago
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