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lesantik [10]
3 years ago
10

Observe the equation below, can a value be found for x to make the equation true? Why or why not? 0=4x

Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0
You have written 0 = 4x.

The value of x that makes it true is x = 0, given that 4 times 0 is 0.

Nevertheless, I think you wanted to write 0 = 4 ^x (this is 4 raised to the power 4).

In that case, there is not any valued of x that satisfies the equation. This is, the equation is always false.

That is because, there is not any value of x for which 4^x is zero. The range of this function is al the positive values of x, which exclude zero.
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B, D, and E
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The absolute value of 37 is also 37.
When you distribute the negative in the parenthesis the -37 becomes positive.
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Step-by-step explanation:Above


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Read 2 more answers
Select ALL the correct answers.
IgorC [24]

Answer:

A. 4(x - 4) + 2(3x² + 3x - 20)

C. (11x² + 7x - 55)-(5x² - 3x + 1)

F. (3x² + 5x - 28) + (3x² + 5x - 28)

Step-by-step explanation:

Given:

(3x-7)(2x+8)

= 6x² + 24x - 14x - 56

=6x² + 10x - 56

A. 4(x - 4) + 2(3x² + 3x - 20)

= 4x - 16 + 6x² + 6x - 40

= 6x² + 10x - 56

B. (3x² + 5x - 28) - (2x² + 4x + 28)

= 3x² + 5x - 28 - 2x² - 4x - 28

= x² + x - 56

C. (11x² + 7x - 55)-(5x² - 3x + 1)

= 11x² + 7x - 55 - 5x² + 3x - 1

= 6x² + 10x - 56

D. 4(x - 4) - 2(3x² + 3x - 20)

= 4x - 16 - 6x² - 6x + 40

= - 6x² - 2x + 24

E. (11x² + 7x - 55)-(5x² - 3x + 2)

= 11x² + 7x - 55 - 5x² + 3x - 2

= 11x² - 5x² + 7x + 3x - 55 - 2

= 6x² + 10x - 57

F. (3x² + 5x - 28) + (3x² + 5x - 28)

= 3x² + 5x - 28 + 3x² + 5x - 28

= 6x² + 10x - 56

7 0
3 years ago
Convert the repeating nonterminating 0.1515...
solniwko [45]
303/2000 is the answer to your question
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