Fraction A 5/& , Fraction B 3/4 ......

Mathematics

1 answer:

jasenka [17]2 years ago

6 0

Answer:

Five Sixths is the word form of Fraction A.

Three fours is the word form of Fraction B.

Step-by-step explanation:

Fraction A = 5 / 6

Its word form = Five Sixths

Fraction B = 3 / 4

Its word form = Three Fours

You might be interested in

Find the surface area of a rectangular prism with base 4 m by 5 m and height 8 m.

Andre45 [30]

Answer:

Step-by-step explanation:

surface area=area of sides +area of top and bottom

=2(4+5)×8+2×(4×5)

=2[(9×8)+20]

=2[72+20]

=2×92

=184 m²

4 0

3 years ago

Read 2 more answers

Select the correct answer.

Ivan

Diagram needed please!!

7 0

3 years ago

Read 2 more answers

Is sin theta=5/6, what are the values of cos theta and tan theta?

mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill$

$\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}$