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Katarina [22]
2 years ago
14

A pool company is creating a blueprint for a family pool and a similar dog pool for a new client. Which statement explains how t

he company can determine whether pool ABCD is similar to pool EFGH? quadrilaterals ABCD and EFGH Translate EFGH so that point F of EFGH lies on point B of ABCD, then dilate EFGH by the ratio segment EF over segment AB. Translate EFGH so that point E of EFGH lies on point A of ABCD, then translate EFGH so that point F of EFGH lies on point B of ABCD. Translate EFGH so that point E of EFGH lies on point A of ABCD, then dilate EFGH by the ratio segment AB over segment EF. Translate EFGH so that point F of EFGH lies on point B of ABCD, then translate EFGH so that point E of EFGH lies on point A of ABCD.
plzzzzzzzz help
Mathematics
2 answers:
ivann1987 [24]2 years ago
7 0

Answer:

B.

Step-by-step explanation:

These are the multiples of 15 but what you are probably asking or what are the factors of 15. If ABCD and EFGH are similar, then you should be able to line up corresponding points (for example, A corresponds to E, B corresponds to F). if they're different sizes, you should then dilate one of them so that they are the exact same size.

chubhunter [2.5K]2 years ago
3 0

if ABCD and EFGH are similar, then you should be able to line up corresponding points (for example, A corresponds to E, B corresponds to F). if they're different sizes, you should then dilate one of them so that they are the exact same size.

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You are an assistant director of the alumni association at a local university. You attend a presentation given by the university
NNADVOKAT [17]

Answer:

(0.102, -0.062)

Step-by-step explanation:

sample size in 2018 = n1 = 216

sample size in 2017 = n2 = 200

number of people who went for another degree in 2018 = x1 = 54

number of people who went for another degree in 2017 = x2 = 46

p1 = x1/n1 = 0.25

p2 = x2/n2 = 0.23

At 95% confidence level, z critical = 1.96

now we have to solve for the confidence interval =

<h2> p1 -p2 ± z*\sqrt{((1-p1)*p1)/n1 + ((1-p2)*p2/n2}</h2>

0.25 -0.23 ± 1.96*\sqrt{((1 - 0.25) * 0.25)/216 + ((1 - 0.23) *0.23/200}

= 0.02 ± 1.96 * 0.042

= 0.02 + 0.082 = <u>0.102</u>

= 0.02 - 0.082 = <u>-0.062</u>

<u>There is 95% confidence that there is a difference that lies between  - 0.062 and 0.102 on the proportion of students who continued their education in the years, 2017 and 2018.</u>

<u></u>

<u>There is no significant difference between the two.</u>

5 0
3 years ago
The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

7 0
3 years ago
What is the scale factor of point E (original point) to point F (new point) with P as the center of dilation.
babunello [35]

Answer:

Answer is last alternative

scale factor (2)

8 0
2 years ago
When 0.3(4x - 8) - 0.5(2.4x + 4) is simplified what is the resulting expression?
LUCKY_DIMON [66]
0.3(4x-8)-0.5(2.4x+4)
1.2x-2.4-1.2x+2
x-0.4
4 0
3 years ago
The length of a rectangle is four more than triple the width. if the perimeter is 120 inches, find the dimensions.
mezya [45]
120/2=60 (sum of both lengths)
4x+4=60
4x=56
x=14

length=46
width=14
5 0
2 years ago
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