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Rama09 [41]
3 years ago
12

An article bought for rs. 800 is sold for 5/4 of the cost price.Find the profit percentage.​

Mathematics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

25%

Step-by-step explanation:

Step 1: Find the sale price

First, we have to find the price it was sold for.

\longmapsto 5/4 of 800 = 5/4 * 800

\frac54 * 800 = \\\\\frac{4000}{4}  = 1000\\\\

The article was sold for rs. 1000

Step 2: Finding the percentage

To find the percentage, we have to divide the sale price over the cost of the article

\frac{1000}{800} = \frac54 = 1.25 = 125percent

The cost of the article is 100% or 1

1.25 - 1 = 0.25  - or- 25percent

25%

-Chetan K

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Answer:

w = 12

Step-by-step explanation:

2(4w-1)=-10(w-3)+4

2*4w + 2*-1 = (10*w + 10*-3) + 4

8w - 2 = 10w - 30 + 4

8w - 2 = 10w - 26

26 - 2 = 10w - 8w

24 = 2w

w = 24/2

w = 12

Check:

2((4*12)-1) = 10(12-3) + 4

2(48-1) = 10(9) + 4

2*47 = 90 + 4 = 94

7 0
3 years ago
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The price of gold is often reported per ounce. At the end of 2005, this price was $513. At the end of 2015, it was $1060. By wha
erastova [34]

Answer:

106.63%.

Step-by-step explanation:  

We have been given that at the end of 2005, this price was $513. At the end of 2015, it was $1060.

To find the percentage of the price per ounce of gold increase we will use % increase formula.

\text{Percent Increase}=\frac{\text{Final value-Initial value}}{\text{Initial value}}\times 100

Let us substitute our given values in above formula.

\text{Percent Increase}=\frac{1060-513}{513}\times 100

\text{Percent Increase}=\frac{547}{513}\times 100

\text{Percent Increase}=1.0662768031189084\times 100

\text{Percent Increase}=106.62768031189084\approx 106.63

Therefore, the price of per ounce of gold increased by 106.63%.

5 0
3 years ago
A 2-column table with 4 rows. Column 1 is labeled Store with entries A, B, C, D. Column 2 is labeled Advertised Bread Prices wit
attashe74 [19]

answer is C

Step-by-step explanation:

i got it right and it looked like no one would help you so

6 0
3 years ago
I need help with this
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That equals 27 hope this helps
3 0
3 years ago
The half-life of radium-226 is 1600 years. Suppose we have a 27-mg sample.
slega [8]

A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)

The amount of sample that will remain after 4000 years is; 4.8357 mg

The number of years that it will take for only 17 mg of the sample to remain is;  1076 years

<h3>How to solve exponential decay function?</h3>

A) Using the model for radioactive decay;

m(t)= m₀e^(-rt)

where;

m₀ is initial mass

r is rate of growth

t is time

Thus, we are given;

m₀ = 27 mg

r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043

and so we have;

m(t) = 27e^(-0.00043t)

c) The amount that will remain after 4000 years is;

m(4000) = 27e^(-0.00043 * 4000)

m(4000) = 27 * 0.1791

m(4000) = 4.8357 mg

d) For 17 mg to remain;

17 = 27e^(-0.00043 * t)

17/27 = e^(-0.00043 * t)

In(17/27) = -0.00043 * t

-0.4626/-0.00043 = t

t = 1076 years

Read more about Exponential decay function at; brainly.com/question/27822382

#SPJ1

5 0
1 year ago
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