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valentinak56 [21]
3 years ago
5

Icelare eoeo of the author o not used​

Mathematics
1 answer:
kirill115 [55]3 years ago
4 0
Can not tell when u are trying to say so I cannot help
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Linda owns 4 shares of a certain stock. Yesterday the total value of her shares went down by 32 dollars. What was the change in
Annette [7]

Answer:

The value of each share decreased by $8.

Step-by-step explanation:

Number of shares of a certain stock Linda owned = 4

Total value of shares went down by = $32

So find the change in value of each share.

Solution:

Let the total value of each share in dollars be = x

Value of 4 shares in dollars will be = 4x

The total value of shares went down by $32

So, new value of 4 shares = 4x-32

New value of each share = \frac{New\ value\ of\ total\ shares}{4}

⇒ \frac{4x-32}{4}

Splitting the denominators.

⇒ \frac{4x{{4}-\frac{32}}{4}

⇒ x-8

Original value of each share in dollars was = x

New value of each share in dollars = x-8

Thus, we can see that the value of each share decreased by $8.

6 0
3 years ago
If H= 2f over m+1, solve the equation for f
Viefleur [7K]
H = 2f / (m+1)
[multiply by (m+1)]
h(m+1) = 2f
[divide by 2]
f = (h (m + 1)) / 2

3b / (b+2) = 12 / (b+2)
[multiply by (b+2)]
3b = 12
[divide by 3]
b = 4

3 / (6x + 1) / 2 = 8 / (x + 4) / 3
[multiply both denominators to mike one denominator]
3 / 8(6x+1) = 8 / 3(x+4)
[expand brackets]
3 / (48x + 8) = 8 / (3x + 12)
[multiply by (48x + 8)]
3 = 8(48x + 8) / (3x+12)
[multiply by (3x+12)]
3(3x +12) = 4(48x + 8)
[simplify]
9x + 36 = 192x + 32
173x = 4
x = 4 / 173
8 0
3 years ago
Please I need help ASAP! I don't know any of the answers. For the second question, I accidentally clicked on it.
valkas [14]
PART A :
A,B,C,D
Because if the spinner was spinning on time it would have either landed on any of the given parts a,b,c,d once
PART B:
A and B
They are equally likely to occur because both of them have a portion of 90 degrees.
Hopefully my answer helped :)
3 0
3 years ago
What is 7 1/5 written as a percent?
DanielleElmas [232]
7 1\5=7x5+1=36\5
36\5 x 100=720%
4 0
3 years ago
Read 2 more answers
Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
2 years ago
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