I need help please I don’t know what to it is due today
2 answers:
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Answer:
32760 ways
Step-by-step explanation:
Given
Number of Candidates = 15
Job Positions = 4
Required:
Number of outcomes
This question represent selection; i.e. selecting candidates for job positions;
This question can be solved in any of the following two ways
Method 1.
The first candidate can be chosen from any of the 15 candidates
The second candidate can be chosen from any of the remaining 14 candidates
The third candidate can be chosen from any of the remaining 13 candidates
The fourth candidate can be chosen from any of the remaining 12 candidates
Total Possible Selection = 15 * 14 * 13 * 12
<em>Total Possible Selection = 32760 ways</em>
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Method 2:
This can be solved using permutation method which goes thus;
Where n = 15 and r = 4
So;
becomes
<em>Hence, there are 32760 ways</em>
Given:
p = 7.6% = 0.076, the percentage of people who stay overnight at the hospital.
E = 1.5% = 0.015, margin of error
95% confidence interval.
The standard error is
Es =
where
n = the sample size.
The margin of error is
where
z* = 1.96 at the 95% confidence level.
Because the margin of error is given, there is no need to calculate it.
The 95% confidence interval is
p +/- E = 0.076 +/- 0.015 = (0.061, 0.091) = (6.1%, 9.1%)
Answer:
The 95% confidence interval is between 6.1% and 9.1%.
p = 7.6% = 0.076, the percentage of people who stay overnight at the hospital.
E = 1.5% = 0.015, margin of error
95% confidence interval.
The standard error is
Es =
where
n = the sample size.
The margin of error is
where
z* = 1.96 at the 95% confidence level.
Because the margin of error is given, there is no need to calculate it.
The 95% confidence interval is
p +/- E = 0.076 +/- 0.015 = (0.061, 0.091) = (6.1%, 9.1%)
Answer:
The 95% confidence interval is between 6.1% and 9.1%.