A 1200 kg car moves due north with a speed of 15m/s. An identical car moves due east with the same speed of 15m/s what are the d

Question

sergeinik [125]

3 years ago

12

A 1200 kg car moves due north with a speed of 15m/s. An identical car moves due east with the same speed of 15m/s what are the d

irection and the magnitude of the system’s total momentum

Physics

1 answer:

Inga [223] · Answer 1 · 2022-11-06T10:40:16+03:00

a.

The direction of the total momentum is 45°

The momentum of the first car is given by p = mv where m = mass of car = 1200 kg and v = velocity of car = 15 m/sj (since it moves due north).

So, p = mv

= 1200 kg × (15 m/s)j

= (18000 kgm/s)j

Also, the momentum of the identical car, p' = mv' where m = mass of car = 1200 kg and v' = velocity of car = (15 m/s)i (since it moves due east).

So, p' = mv'

= 1200 kg × (15 m/s)i

= (18000 kgm/s)i

So, the total momentum of the system P = p + p'

= (18000 kgm/s)j + (18000 kgm/s)i

= (18000 kgm/s)i + (18000 kgm/s)j

The direction of the total momentum of the system P is gotten from

tanФ = p'/p

= 18000 kgm/s ÷ 18000 kgm/s

= 1

Ф = tan⁻¹(1)

= 45°