Answer:
Explanation:
Let the magnitude of magnetic field be B .
flux passing through the coil's = area of coil x field x no of turns
Φ = 3.13 x 10⁻⁴ x B x 135 = 422.55 x 10⁻⁴ B .
emf induced = dΦ / dt , Φ is magnetic flux.
current i = dΦ /dt x 1/R
charge through the coil = ∫ i dt
= ∫ dΦ /dt x 1/R dt
= 1 / R ∫ dΦ
= Φ / R
Total resistance R = 61.1 + 44.4 = 105.5 ohm .
3.44 x 10⁻⁵ = 422.55 x 10⁻⁴ B / 105.5
B = 3.44 x 10⁻⁵ x 105.5 / 422.55 x 10⁻⁴
= .86 x 10⁻¹
= .086 T .
The calculated magnitude is 6.73 x 10³ V/m.
AMU is described as being one-twelfth the mass of a carbon-12 atom (12C). C makes up more than 98% of the carbon that can be found in nature, making it the most prevalent isotope. The magnitude of the field is the change in potential across a small distance in the indicated direction divided by that distance.
Potential difference = 8.20 kV= 8.20 x 10³ V
radius= 19.4/100=0.194 m
total distance that is circumference of the circle= 2πr =2 x 3.14 x 0.194
= 1.218 m
therefore Magnitude= 8.20 x 10³ / 1.218
=6.73 x 10³ V/m
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They have a negative oxidation number because nonmetals gain electrons, thus making them negatively charged ions (anions). Metals become cations and have a positive charge because they lose electrons.
Answer:
If by 1.5 MJ you mean 1.5E6 Joules then
W = P t = power X time
W / t = P power
P = 1.5E6 J / 600 sec = 2500 J / s
P = I V
a) I = 2500 J/s / (240 J/c) = 10.4 C / sec = 10.4 amps
b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs
c) E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules
