The answer is
The memo line
Answer:
Kindly find the code snippet in the explanation written in kotlin language
Explanation:
fun main(args: Array<String>) {
var num:Int
println("Enter a num")
num= Integer.valueOf(readLine())
for(i in num downTo 1){
if(i==num){
print("Ready!")
print(" ")
}
print(i)
print(" ")
if(i==1){
print(" ")
print("Go!")
}
}
}
This function too can also work
fun numTo(num:Int){
if (num>0) for(i in num downTo 1) print("$i ")
println("Go!")
Answer:
see answer below
Explanation:
the equation is given by
k=ko* e^(-Q/RT)
then replacing the known values
k=1200 min⁻¹ e^[-8000 cal/mole/ (1.987 cal/mole K *T)]
then replacing values of T every 50 K from 100 to 500 K we get the series of values
![\left[\begin{array}{ccc}T&k\\100&3.924*10^{-15} min ^{-1} \\150&2.643*10^{-9} min ^{-1} \\200&2.17*10^{-6} min ^{-1} \\250&1.216*10^{-4} min ^{-1} \\300&1.781*10^{-3} min ^{-1} \\350&0.012 min ^{-1} \\400&0.051 min ^{-1} \\450&0.156 min ^{-1} \\500&0.382 min ^{-1} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DT%26k%5C%5C100%263.924%2A10%5E%7B-15%7D%20min%20%5E%7B-1%7D%20%5C%5C150%262.643%2A10%5E%7B-9%7D%20min%20%5E%7B-1%7D%20%5C%5C200%262.17%2A10%5E%7B-6%7D%20min%20%5E%7B-1%7D%20%5C%5C250%261.216%2A10%5E%7B-4%7D%20min%20%5E%7B-1%7D%20%5C%5C300%261.781%2A10%5E%7B-3%7D%20min%20%5E%7B-1%7D%20%5C%5C350%260.012%20min%20%5E%7B-1%7D%20%5C%5C400%260.051%20min%20%5E%7B-1%7D%20%5C%5C450%260.156%20min%20%5E%7B-1%7D%20%5C%5C500%260.382%20min%20%5E%7B-1%7D%20%5Cend%7Barray%7D%5Cright%5D)
Answer:
Following is the program in C language :
#include <stdio.h> // header file
#define n 5 // macro
int main() main function
{
int a[n],k1; // variable and array declaration
printf("Enter the element:\n");
for(k1=0;k1<n;++k1) //iterating the loop
{
scanf("%d",&a[k1]);//Read the values by user
}
printf("Output in Reverse Order:\n");
for(k1=n-1;k1>=0;--k1)//iterating the loop
{
printf(" %d ",a[k1]); //Display the values
}
return 0;
}
Output:
Enter the element:
4
3
45
67
89
Output in Reverse Order: 89 67 45 3 4
Explanation:
Following is the description of the program
- Define a macro "n" with value 5 after the header file.
- Declared an array "a" and defined the size of that array by macro i.e "n".
- Read the value by the user by using scanf statement in the array "a"
- Finally In the last for loop display the values of array "a" by space.
Answer:
Is there an early pay discount?
Explanation:
This determines and instructs what path the code should take,
if there is no early pay discount, it has different instructions to follow.
