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3 years ago

15

How to make this circuit for simulating on Proteus.

1 answer:

morpeh [17]3 years ago

5 0

U can use the area rule formula

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In a Series circuit with two identical loads, the voltage across each load will be:

mel-nik [20]

<h3>Option A</h3>

In a Series circuit with two identical loads, the voltage across each load will be: the same

<h3><u>Explanation:</u></h3>

A series circuit is one with total the loads in a row. There is barely ONE path for electricity to pass. If this circuit was a series of flashbulbs, and one left out, the left bulbs would switch off. T

he current in a series circuit is universally the same and the voltage over the circuit is the amount of the unique voltage drops over each component. The voltage referred to as a series circuit is equivalent to the amount of the individual voltage drops.

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3 years ago

Everyone has only one learning style. True or false? hurry pleasle this exp carees class

Temka [501]

Answer:

This is False because people can have more than 1

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3 years ago

Which of the following is the BEST example of statistical evidence?

alexandr1967 [171]

Well it would help if there was a picture but wild guess i’m going with B or the second choice.

5 0

3 years ago

A long, circular aluminum rod is attached at one end to a heated wall and transfers heat by convection to a cold fluid.

Trava [24]

Answer:

a. Heat removal rate will increase

b. Heat removal rate will decrease

Explanation:

Given that

One end of rod is connected to the furnace and rod is long.So this rod can be treated as infinite long fin.

We know that heat transfer in fin given as follows

$Q_{fin}=\sqrt{hPKA}\ \Delta T$

We know that area

$A=\dfrac{\pi}{4}d^2$

Now when diameter will triples then :

$A_f=\dfrac{\pi}{4}{\left (3d \right )}^2$

$A_f=9A$

$Q'_{fin}=\sqrt{9hPKA}\ \Delta T$

$Q'_{fin}=3\sqrt{hPKA}\ \Delta T$

$Q'_{fin}=3Q$

So the new heat transfer will increase by 3 times.

Now when copper rod will replace by aluminium rod :

As we know that thermal conductivity(K) of Aluminium is low as compare to Copper .It means that heat transfer will decreases.

3 0

3 years ago

The amplitudes of the displacement and acceleration of an unbalanced motor were measured to be 0.15 mm and 0.6 g, respectively.

PilotLPTM [1.2K]

Answer:

N=945.76 RPM

Explanation:

Given that

A= 0.15 m

Acceleration = 0.6 g

a=0.6 x 9.81 m/s²

a= 5.886 m/s²

We know that acceleration a given as

a = ω² A

ω=Angular speed

$\omega=\sqrt{\dfrac{0.6\times 9.81}{0.6\times 10^{-3}}}$

ω=99.04 rad/s

We know that

$\omega=\dfrac{2\pi N}{60}\\\\N=\dfrac{60\times \omega}{2\pi }$

$N=\dfrac{60\times 99.04}{2\pi }$

N=945.76 RPM

Therefore the speed of the motor will be 945.76 RPM.

6 0

4 years ago