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2 years ago

Rectangular prism has a length of 8 meters, a width of 6 meters, and a height of 3 meters.

Mathematics

2 answers:

Leni [432]2 years ago

7 0

Answer:

V=8×6×3

Step-by-step explanation:

Given that,

the rectangular prism has ;

length=8meters
width=6meters
height=3meters

As we know, 

volume =length×width×height
V=8×6×3

fenix001 [56]2 years ago

4 0

Answer:

V = 8 * 6 * 3

Step-by-step explanation:

The volume of a rectangular prism is given by

V = length * Width * height

V = 8 * 6 * 3

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. y - 6 = 4(x - 4) Which of the following shows a graph of the equation above?

Phantasy [73]

Answer:

Step-by-step explanation:

7 0

3 years ago

(2x + y = -2 (5x + 3y = -8 Solve by substitution

aliya0001 [1]

(2, -6)

Step-by-step explanation:

y = -2 - 2x

5x + 3 (-2-2x) = - 8

5x - 6 - 6x = - 8

-x - 6 = 8

- 6 + 8 = x

2 = x

x = 2

y = -2 -2x

y = -2 -2(2)

y = -2 -4

y = -6

(x, y) = (2, -6)

3 0

3 years ago

Read 2 more answers

A line passes through the points (-1, -1)

Allisa [31]

Given:

A line passes through the points (-1, -1) and (5,8).

To find:

Which points lie on the same line?

Solution:

If a line passes through two points, then the equation of the line is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

A line passes through the points (-1, -1) and (5,8). So, the equation of the line is:

$y-(-1)=\dfrac{8-(-1)}{5-(-1)}(x-(-1))$

$y+1=\dfrac{8+1}{5+1}(x+1)$

$y+1=\dfrac{9}{6}(x+1)$

$y+1=\dfrac{3}{2}(x+1)$

Multiply both sides by 2.

$2(y+1)=3(x+1)$

$2y+2=3x+3$

$2y=3x+3-2$

$y=\dfrac{3}{2}x+\dfrac{1}{2}$

So, the equation of the line is $y=\dfrac{3}{2}x+\dfrac{1}{2}$ .

Now, check each point for this equation.

Putting $x=-3$ , we get

$y=\dfrac{3}{2}(-3)+\dfrac{1}{2}$

$y=\dfrac{-9+1}{2}$

$y=\dfrac{-8}{2}$

$y=-4$

Similarly,

For $x=9,y=15$ .

For $x=1,y=2$ .

For $x=4,y=6.5$ .

For $x=3,y=5$ .

For $x=-2,y=-2.5$ .

Therefore, the points (-3,-4), (9,14), (1,2) and (3,5) lie on the same line but the points (4,7) and (-2,-2) are not on that line.

6 0

3 years ago

Solve the following equation simultaneously 2a-3b+10=0, 10a+6b=8

tia_tia [17]

$2a -3b +10 =0\\\\10a+ 6b -8 =0\\\\\text{Using cross multiplication method}\\\\\\ \dfrac a{(-3)(-8) - 6(10)} = \dfrac b{10(10) - 2(-8)} = \dfrac 1{ 2(6) - (-3)(10)}\\\\\\\implies \dfrac a{24-60} = \dfrac b{100+16} = \dfrac 1{12+30}\\\\\\\\\implies -\dfrac {a}{36} = \dfrac b{116} = \dfrac 1{42}\\\\\\\text{Hence}\\\\a = - \dfrac{36}{42} = -\dfrac 67 \\\\\\ b= \dfrac{116}{42} = \dfrac{58}{21}$

3 0

2 years ago

What is an equation of the line that passes through the points (0, -7) and (-8, 3)?

avanturin [10]

Answer (assuming it can be in slope-intercept form):

$y = -\frac{5}{4} x-7$

Step-by-step explanation:

1) First, find the slope of the line by using the slope formula, $m = \frac{y_2-y_1}{x_2-x_1}$ . Substitute the x and y values of the given points into the formula and solve:

$m = \frac{(3)-(-7)}{(-8)-(0)}\\m = \frac{3+7}{-8-0} \\m = \frac{10}{-8} \\m = -\frac{5}{4}$

So, the slope is $-\frac{5}{4}$ .

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ to write the equation of the line in point-slope form. Substitute real values for the $m$ , $x_1$ , and $y_1$ in the formula.

Since $m$ represents the slope, substitute $-\frac{5}{4}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of one point the line intersects, choose any one of the given points (either one is fine, it will equal the same thing at the end) and substitute its x and y values into the formula as well. (I chose (0, -7), as seen below.) Then, isolate y to put the equation in slope-intercept form and find the following answer:

$y-(-7) = -\frac{5}{4} (x-(0))\\y + 7 = -\frac{5}{4} x\\y = -\frac{5}{4} x-7$

7 0

3 years ago