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2 years ago

The figure shows triangle DEF and line segment BC, which is parallel to EF:

Mathematics

2 answers:

Korvikt [17]2 years ago

6 0

Part A: Yes, Triangle DEF and DBC are the same triangle, but DBC is smaller than DEF because it is just a cut off of DEF.

Part B: I am pretty sure it is angle C.

Part C: I am pretty sure it is angle D.

navik [9.2K]2 years ago

6 0

Answer:

Step-by-step explanation:

Part A.

m < B = m < E (corresponding angles, (BC parallel to EF))

m < C = m < F ( as above)

So triangles DBC and DEF are similar ( by 2 equal angles).

Part B.

Line segment BC ( as they are both opposite < D)

Part C.

< C as its in same relative position to < F.

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Please help me with this!

ZanzabumX [31]

9514 1404 393

Answer:

2 1/2 feet

Step-by-step explanation:

The Pythagorean theorem is not useful in this problem.

If you reflect the triangle over the vertical line, you find that line to be the altitude of an equilateral triangle. That is, all of the vertex angles are 60°.

The base of that equilateral triangle is necessarily twice the length of the base of the triangle shown. All sides of the equilateral triangle are the same length, so all are 5 ft. The base of the triangle shown is half that.

The base (short leg) of the triangle shown is 2 1/2 feet.

_____

Since angles are given, this can be solved using trigonometry. The short leg will be (5 ft)·cos(60°) = (5 ft)(0.5) = 2.5 ft. (The cosine of 60° is one of the few exact rational values of trig functions of exact angles measured in degrees.)

5 0

3 years ago

The Lopez family is traveling.The trip will take 8 1/4 hours by train or 6 2/3 hours by car.How many hours shorter is the trip b

aleksklad [387]

I think it is 1 and 7/12

3 0

4 years ago

Create a system of equations that includes one linear equation and one quadratic equation.Part 1. Show all work in solving your

xxMikexx [17]

Answer:

The simplest system:

y = x
y = x²

Solve by eliminating y:

x² = x
x(x - 1) = 0
x₁ = 0
x₂ = 1

Then the value of y:

y₁ = 0
y₂ = 1

The graphical solution is attached

(0, 0), (1, 1)

4 0

3 years ago

Anyone? Can help !!!

il63 [147K]

Answer:

C.g(x) = 5x²

Step-by-step explanation:

To find the equation for the function g(x), use the format for a quadratic equation. Without any up/down and left/right shifts, the form is y = ax².

Substituting "x" and "y" into the equation tells you if a point is on the graph.

"a" tells you the vertical stretch (greater than 1) or compression (greater than 0, less than 1).

In f(x) = x², a = 1 even though it's not written.

Use the point (1, 5) on g(x) and substitute it into the form for a quadratic function. Remember points are (x, y), so x = 1 and y = 5.

g(x) = ax²

y = ax² In function notation, g(x) replaces the "y". Switch it back to "y".

5 = a(1)² Substitute x = 1 and y = 5

5 = a(1) Solve the exponent first. (1)² = 1

5 = a When you multiply "a" by 1, the answer is just "a".

a = 5 Solved for "a". Put variable on left side for standard formatting.

With the quadratic form, substitute "a" into g(x).

y = ax²

g(x) = 5x²

7 0

3 years ago

Which of the following is equivalent to x+1/y divided by g+1/h

Vikki [24]

Answer:

B) x + 1/y times h/g+1

Step-by-step explanation:

We need to divide $\frac{x+1}{y}$ by $\frac{g+1}{h}$ then match with given choices to find the correct equivalent result.

where given choices are:

A) x/y times h/g

B) x + 1/y times h/g+1

C) x+ 1/y divided h/g+1

D) y/x+1 divided g+1/h

So let's divide $\frac{x+1}{y}$ by $\frac{g+1}{h}$

$\frac{\left(\frac{x+1}{y}\right)}{\left(\frac{g+1}{h}\right)}$

we are allowed to flip the bottom fraction and change division sign into multiplication. So we get:

$=\left(\frac{x+1}{y}\right)\cdot\left(\frac{h}{g+1}\right)$

Hence correct choice is: B) x + 1/y times h/g+1

3 0

3 years ago