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likoan [24]
2 years ago
15

Pppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
Salsk061 [2.6K]2 years ago
6 0

Answer:

Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaàaaaaaaaaaaaaaaa

Step-by-step explanation:

à isn't the same ️️✨

IrinaK [193]2 years ago
4 0

Answer:

P

Step-by-step explanation:

Findings are not the same

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Help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
laiz [17]

Answer:

sound like a personal problem

Step-by-step explanation:

cuz

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3 years ago
What is the range of possible sizes for side x? _ < x < _
qwelly [4]

Answer:

2.8 < x < 5.8

Step-by-step explanation:

We must apply the Triangle Inequality Theorem which states that for any triangle with sides a, b, and c:

a + b > c

b + c > a

c + a > b

Here, let's arbitrarily denote a as 4.1, b as 1.3, and c as x. So, let's plug these values into the 3 inequalities listed above:

a + b > c  ⇒  4.1 + 1.3 > x  ⇒  5.8 > x

b + c > a  ⇒  1.3 + x > 4.1  ⇒  x > 2.8

c + a > b  ⇒  x + 4.1 > 1.3  ⇒  x > -2.8

Look at the last two: clearly if x is greater than 2.8 (from the second one), then it will definitely be greater than -2.8 (from the third), so we can just disregard the last inequality.

Thus, the range of possible sizes for x are:

2.8 < x < 5.8

<em>~ an aesthetics lover</em>

8 0
2 years ago
Read 2 more answers
The ratio of white socks to brown socks is <br> PLZ HELP ASAP
Alex73 [517]

Answer:

0.875 is the ratio from white to brown socks.

6 0
3 years ago
A Confidence interval is desired for the true average stray-load loss mu (watts) for a certain type of induction motor when the
Vaselesa [24]

Answer:

A sample size of 35 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the width W as such

W = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large must the sample size be if the width of the 95% interval for mu is to be 1.0:

We need to find n for which W = 1.

We have that \sigma^{2} = 9, then \sigma = \sqrt{\sigma^{2}} = \sqrt{9} = 3. So

W = z*\frac{\sigma}{\sqrt{n}}

1 = 1.96*\frac{3}{\sqrt{n}}

\sqrt{n} = 1.96*3

(\sqrt{n})^2 = (1.96*3)^{2}

n = 34.57

Rounding up

A sample size of 35 is needed.

3 0
3 years ago
What is the answer to 2/3 ( c-18)= 7, please show the steps
Roman55 [17]

(2/3)*(c-18)=7 <em>(Multiply terms on both sides of equation by 3)</em>

2(c-18)=21

2c-36=21

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4 0
3 years ago
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