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likoan [24]
3 years ago
15

Pppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
6 0

Answer:

Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaàaaaaaaaaaaaaaaa

Step-by-step explanation:

à isn't the same ️️✨

IrinaK [193]3 years ago
4 0

Answer:

P

Step-by-step explanation:

Findings are not the same

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Fraction has fraction in both
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5x-4y=-18 what is the three point on a graph for this equation
Tju [1.3M]
(1)Draw the "y" line . It goes up and down. 
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<span>Start at -20 and go to 10 </span>
<span>(2)Draw the "x" line. it goes side to side. </span>
<span>place the x line at the zero point of the y line. I'm sure you will see your paper looks like the letter "t". Perfectly at a right angle. you could use the corner of a book to square it. </span>

<span>Now for the maths 5x - 4y = -18. The most important symbol here is the "=" sign. </span>
<span>(3) rearrange the equation so that y is on one side of "=" and x is on the other side. </span>
<span>Remember if you add 10 to one side the of "=" , then for it to be equal, add 10 to the other. side also </span>
<span>so add 4y to both sides. add 18 to both sides . divide the whole of each side by 4. </span>
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<span>(7) </span>
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5 0
3 years ago
Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

3(\frac{y}{400})

Therefore,

\frac{dy}{dt}=0-3(\frac{y}{400}) or just

\frac{dy}{dt}=-\frac{3y}{400} and in terms of time,

-\frac{3t}{400}

Thus, our equation is

y=28e^{-\frac{3t}{400} and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0
3 years ago
At the beginning of this month, the balance of Carl's checking account was $437.55. So far this month, he has received a paychec
Nuetrik [128]
Again, just simple addition and subtraction: $1,034.52
5 0
3 years ago
Read 2 more answers
Look at the figure, . Find the values of ​x and y. x = 5, y = 7 x = 6, y = 8 x = 6, y = 9 x = 7, y = 10
Colt1911 [192]

Answer:

x = 6, y = 9

Step-by-step explanation:

One of the properties of a parallelogram is

The diagonals bisect each other, hence

2x = y + 3 → (1)

2y = 3x → (2)

Rearrange (1) in terms of y by subtracting 3 from both sides

y = 2x - 3 → (3)

Substitute y = 2x - 3 into (2)

2(2x - 3) = 3x ← distribute left side

4x - 6 = 3x ( add 6 to both sides )

4x = 3x + 6 ( subtract 3x from both sides )

x = 6

Substitute x = 6 into (3) for value of y

y = (2 × 6) - 3 = 12 - 3 = 9

Hence x = 6 and y = 9

5 0
4 years ago
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