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muminat
2 years ago
14

What is the perimeter of the inside of the track?

Mathematics
2 answers:
nekit [7.7K]2 years ago
7 0

Answer:

Well add up the sides you can make the curving part into a full circle and calculate for the circumference.

So if the half of the circle straight part is 62 you times it by π. But π (pi) can be a fraction and a decimal: 22/7 or 3.14 although (pi) is 3.14 that is because after .14 there is ton of number so it constantly continues.

Method:

C = 2πr

or

C = πr

I hope this gives you a hint.

lions [1.4K]2 years ago
5 0

Answer:

394.68 m

Step-by-step explanation:

The 2 ends are half circles, so together they make a circle.

The diameter is 62 m, so the circumference is pi x diameter, or 3.14 x 62 = 194.68.

The top and bottom parts of the track are each 100 m, so add 2 of them = 200 m.

Add all 3 parts 194.68 + 200 = 394.68 m.

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3 years ago
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Can someone please help me
Marrrta [24]

Based on the knowledge of <em>trigonometric</em> expressions and properties of <em>trigonometric</em> functions, the value of the <em>sine</em> function is equal to - √731 / 30.

<h3>How to find the value of a trigonometric function</h3>

Herein we must make use of <em>trigonometric</em> expressions and properties of <em>trigonometric</em> functions to find the right value. According to trigonometry, both cosine and sine are <em>negative</em> in the <em>third</em> quadrant. Thus, by using the <em>fundamental trigonometric</em> expression (sin² α + cos² α = 1) and substituting all known terms we find that:

\sin \theta = -\sqrt{1 - \cos^{2}\theta}

\sin \theta = - \sqrt{1 - \left(-\frac{13}{30} \right)^{2}}

sin θ ≈ - √731 / 30

Based on the knowledge of <em>trigonometric</em> expressions and properties of <em>trigonometric</em> functions, the value of the <em>sine</em> function is equal to - √731 / 30.

To learn more on trigonometric functions: brainly.com/question/6904750

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7 0
2 years ago
I need help with my math please help ASAP.
lbvjy [14]

Answer:

1 =30 km

1/3=7,5 km

5=150

Im not sure tho but should be fine

4 0
3 years ago
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. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?
UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u>As we know:</u>

<u />Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \  of\ I-pad}

5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2

a) Thus, the total width of the I-Pads are 61.2 inches.

Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \  of\ Kindles}

4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles \div Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = \frac{99.6}{20} =4.98\ inches

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

5 0
3 years ago
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Tomtit [17]

Answer:

X > -1

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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