2 + ( 4 • 5 ) + 1 = 26 like this
Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
Step-by-step explanation:
5^2 + b^2 = 9^2
25 + b^2 = 81
b^2 = 56
square root both sides and b = 7.48 cm
A=bh
1056=32<span>×b
</span>÷32 ÷32
3<span>3=h
The height is </span>3<span>3 inches.</span>
Answer:
√95 cm
Step-by-step explanation:
To solve, you need to use the pythagorean theorem, or a^2 + b^2 = c^2
The hypotenuse is the c and let one leg be b. You can write:
a^2 + 7^2 = 12^2
a^2 + 49 = 144
Now, you need to solve for a:
a^2 = 144 - 49
a^2 = 95
a = √95 cm, or about 9.75cm
