Answer:
Either (3,b) or (3,e) must be removed to form the above relation to be function.
Step-by-step explanation:
Given the relation between the elements of domain and range. we have to remove the link between two elements so that relation becomes a function.
A function is a relation in which each element in domain set maps into only one element of range set i.e one element can never have two images in range set.
Here, the element 3 in domain set maps into two element b and e in range set. Therefore, to form a function one link must be removed either
f(3)=b or f(3)=e
Hence, either (3,b) or (3,e) must be removed to form the above relation to be function.
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Answer:
ir
Step-by-step explanation:
irregular
regular
what do you notice different?
the both have r, e, g, u, l, a, r, but one has ir at the beginning.
Given side length "a" and angle "A", calculate the diagonals<span><span>
p = square root [( 2a^2 - 2a^2 cos(A) )]
</span>q = </span><span>square root [( 2a^2+ 2a^2 cos(A) )]</span>
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php
side = 36
cos (32) = 0.84805
p = <span>small diagonal = </span>
<span>
<span>
<span>
19.8457652914
</span>
</span>
</span>
<span><span>
</span>
</span>
q =
large diagonal =
<span>
<span>
<span>
69.2108777578
</span>
</span>
</span>
-27. Divide 2 by 3, then -18 by that number to get -27.
