All categories

3 years ago

Please help me please

Mathematics

2 answers:

Tcecarenko [31]3 years ago

4 0

The answer is c have a great day

vichka [17]3 years ago

3 0

$\frac{76}{90}$

-_-

You might be interested in

Hai has 24 video games. Six of his games are sports related and the rest are role-playing games. Which ratio represents the numb

bekas [8.4K]

Answer:

3/4

Step-by-step explanation:

24-6=18--> role playing games

18/24=3/4

8 0

3 years ago

Read 2 more answers

Gina is getting a new bathroom mirror. The rectangular mirror measures 6 meters by 8 meters. What is the amount of space the mir

wolverine [178]

Answer:

D. 48 square meters

Step-by-step explanation:

The rectangular mirror measures 6 meters by 8 meters.

To find the amount of space the mirror will cover, we simply need to find the area of the mirror.

The area of a rectangle is:

A = L * B

where L = length

B = breadth

Therefore, the area of the mirror is:

A = 6 * 8 = 48 square meters

The mirror will cover an area of 48 square meters.

4 0

3 years ago

How many solutions does the system of equations below have? y = –7x − 9 y = 23x − 89

Vlad1618 [11]

Answer: infinitely many solutions

Step-by-step explanation: A system of two equations can be classified as follows:

If the slopes are the same but the y-intercepts are different, the system has no solution.

If the slopes are different, the system has one solution.

If the slopes are the same and the y-intercepts are the same, the system has infinitely many solutions.

5 0

2 years ago

In triangle DEF, segment DJ is a perpendicular bisector of side EF. If EJ is 3y-8 and JF is 7y-40, what is the length of JF?

luda_lava [24]

Answer: The length of JF = 16 units.

Step-by-step explanation:

Given: In triangle DEF, segment DJ is a perpendicular bisector of side EF.

i.e. DJ is perpendicular to EF and DJ divides EF into two equal parts EJ and JF. [The perpendicular bisector is a line that is perpendicular to a line segment and splits it into two congruent segments.]

If EJ is 3y-8 and JF is 7y-40.

Then, $3y-8=7y-40$

$\Rightarrow\ 7y-3y=40-8\\\\\Rightarrow\ 4y=32\\\\\Rightarrow\ y=8 \text{ [Divide both sides by 4]}$

JF= 7(8)-40 =56-40= 16 units

Hence, the length of JF = 16 units.

4 0

3 years ago

Read 2 more answers

Solve.

Ksenya-84 [330]

Solve.

x² + 4x + 4 = 18

A x=−4±3√ 2

B x=2±3√ 2

C x=4±9√ 2

D x=−2±3√2

 $x^2 + 4x + 4 = 18 \\ \\ x^2+4x+4-18= 0 \\ \\ x^2+4x-14=0 \\ \\ x_1_y_2= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \qquad a= 1\qquad b= 4\qquad c= -14 \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{4^2-4(1)(-14)} }{2(1)} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{16-(-56)} }{2} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{72} }{2} \\ \\ \\ x_1= \dfrac{-4+ \sqrt{72} }{2} \qquad\qquad x_2= \dfrac{-4+ \sqrt{72} }{2}\\ \\ \\ x_1= \dfrac{-4+ \sqrt{2^3*3^2} }{2} \qquad\qquad x_2= \dfrac{-4- \sqrt{2^3*3^2} }{2}$

 $x_1= \dfrac{-4+2*3 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 2*3\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4+6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 6\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4}{2} + \dfrac{6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4}{2}- \dfrac{ 6\sqrt{2} }{2} \\ \\ \\ x_1= -2 + 3 \sqrt{2} \qquad\qquad\quad x_2= -2- 3\sqrt{2} \\ \\ \\ \boxed{x= -2\pm 3\sqrt{2} } \to D)$

7 0

4 years ago

Read 2 more answers

Please help me please​

Please help me please