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3 years ago

Please help me with this

Mathematics

1 answer:

Lana71 [14]3 years ago

4 0

Answer:

A) (shirts) 12 multiplied by 3 is 36. (jeans) 19 multiplied by 2 is 38. 38 plus 36 equals 74. 74 minus 3 is 71. her total is 71 dollars

B) (shirts) 9 multiplied by 3 is 27. 16 multiplied by 2 is 32. 27 plus 32 is 59.

Step-by-step explanation:

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Step-by-step explanation:

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Solve the following quadratic equation 6x2 – 7x = 20

siniylev [52]

Answer:

Step-by-step explanation:

6x² - 7x - 20 = 0

Using method of factorization

Rewrite - 7x as a difference

That's

6x² + 8x - 15x - 20 = 0

Factor the expression

That's

2x( 3x + 4) - 5( 3x + 4) = 0

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(2x - 5) (3x + 4) = 0

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3 years ago

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9k - 26 = 6k -8 answer

schepotkina [342]

Answer:

k = 6

Step-by-step explanation:

9k - 26 = 6k - 8

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3 years ago

-2x - 69 = -9x + 29

UkoKoshka [18]

Answer:

x = 98 /7

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Find the tenth term of the expansion (x+ y)¹³

Anon25 [30]

Answer:

$715x^4y^9$

Step-by-step explanation:

Given

$(x + y)^{13$

Required

Determine the 10th term

Using binomial expansion, we have:

$(a + b)^n = ^nC_0a^nb^0 + ^nC_1a^{n-1}b^1 + ^nC_2a^{n-2}b^2 +.....+^nC_na^{0}b^n$

For, the 10th term. n = 9

So, we have:

$(a + b)^n = ^nC_{9}a^{n-9}b^{9$

$(x + y)^{13} = ^{13}C_{9}x^{13-9}y^9$

$(x + y)^{13} = ^{13}C_{9}x^4y^9$

Apply combination formula

$(x + y)^{13} = \frac{13!}{(13-9)!9!}x^4y^9$

$(x + y)^{13} = \frac{13!}{4!9!}x^4y^9$

$(x + y)^{13} = \frac{13*12*11*10*9!}{4!9!}x^4y^9$

$(x + y)^{13} = \frac{13*12*11*10}{4!}x^4y^9$

$(x + y)^{13} = \frac{13*12*11*10}{4*3*2*1}x^4y^9$

$(x + y)^{13} = \frac{17160}{24}x^4y^9$

$(x + y)^{13} = 715x^4y^9$

Hence, the 10th term is $715x^4y^9$

3 0

3 years ago