What is the value of 14(38−14)+33÷9 1 4 ( 38 − 14 ) + 3 3 ÷ 9 ?

Mathematics

1 answer:

finlep [7]2 years ago

6 0

Answer:

339 $\frac{2}{3}$

Step-by-step explanation:

We will use PEMDAS to solve

-><em> I am going to assume you did not mean to have the problem twice as the last part is the same, just formatted differently, but if I am incorrect please let me know</em>

[Given] 14(38−14)+33÷9

[Subtract] 14(24) + 33 ÷ 9

[Multiply and divide] 336 + 3 $\frac{2}{3}$

[Add] 339 $\frac{2}{3}$

Have a nice day! - Note: I found another problem very similar to this where people were saying it is 9 and that this answer is incorrect, but I am not sure how they found it. Just wanted to let you know.

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

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- Heather

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Paul and jose are trying to measure the height of a tree. paul is standing 19m from the foot of the tree and measures the angle

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The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as $x$ .
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:
$cos(59)= \frac{19}{h}$
$h= \frac{19}{cos(59)}$
$h=36.9$
Now we can use the law of sines to find the distance $x$ between Paul and Jose:
$\frac{sin(43)}{36.9} = \frac{sin(16)}{x}$
$x= \frac{36.9sin(16)}{sin(43)}$
$x=14.9$

Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:
$19m+14.9=33.9m$

We can conclude that Jose is 33.9m from the base of the tree.