Try this explanation:
1. if to re-write the given function as:

then it is possible to define its range:
2)
![\lim_{x \to+ \infty}[1- \frac{C}{e^x+C}]=1; \\ \lim_{x \to- \infty}[1- \frac{C}{e^x+C}]=0](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%2B%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D1%3B%20%20%5C%5C%20%5Clim_%7Bx%20%5Cto-%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D0)
answer: (0;1)
The answer is 73,990.0 hope i help
The answer is B because they are congruent triangles.
The absolute value is always non-negative!
So the absolute value of 57 is 57 itself, as it's non-negative (i.e. it's positive or 0).
Opposite value is the number with a different sign: an opposite value of a positive number is negative, so here it will be -57 .
The correct answer is C.