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Alla [95]
2 years ago
8

Quadrilateral ABCD with vertices A(-4, 1), B(-2,3), C(0,-2), and D(-5,-2) Give the coordinates of the image if k=3.

Mathematics
1 answer:
borishaifa [10]2 years ago
3 0

If you're using a coordinate plane, I think it makes a trapezoid

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The probability of an event occurring is 0.08.
vova2212 [387]

Answer:

0.92

Step-by-step explanation:

always equals 1.0

1.0 - 0.08 = 0.92

7 0
3 years ago
Mr.jeff divided his money in the ratio 4:2 between Jon and jack Jon got the smaller amount of $1,256 how much did jack get?
nadezda [96]
Ratio in which Mr.Jeff divided his money between Jack and Jon = 4:2
Let us assume the common ration to be = x
The amount of money that Jon got = $1256
Then
2x = 1256
x = 1256/2
   = 628
Then
The amount of money that Jon got = 4 * 628 dollars
                                                         = 2512 dollars
So the amount that Jack got is $2512. As Jack got the major or the bigger share of the money, so the answer is correct. I hope the procedure for solving the question is also easy for you to understand.
6 0
3 years ago
I really need help with this one <br>it says 8 of the beads are purple in case it's hard to see
Harman [31]
48% of the beads are purple
7 0
3 years ago
Read 2 more answers
What is the distance between points (10,7) and (2,7) on a coordinate plane?<br> please help me
olga nikolaevna [1]
The distance between those two points is 8 because its a straight line...
3 0
3 years ago
Read 2 more answers
Using the given points and line, determine the slope<br><br> (0,32) and (100,212)
suter [353]
To solve for the slope given two lines, use the formula:

(y₂ - y₁)
----------
(x₂ - x₁)

Set one of the points as (x₁, y₁), and the other as (x₂, y₂).

(x₁, y₁) = <span>(0,32)
</span>(x₂, y₂) <span>= (100,212)

plug into corresponding places:


</span>(y₂ - y₁)         (212 - 32)     (180)
----------    =  -------------- = -------
(x₂ - x₁)         (100 - 0)       (100)


180/100 
is your slope

If you want simplified, it will be: 9/5

hope this helps


5 0
3 years ago
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