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WARRIOR [948]
2 years ago
5

ADC is a straight line.

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
8 0

Applying the triangle sum theorem, the size of ∠BDC = 95°.

<h3>What is the Triangle Sum Theorem?</h3>

All three interior angles of any triangle have a sum that equals 180 degrees, based on the triangle sum theorem.

The diagram attached below shows the following:

  • m∠BAD = 55°
  • m∠BCD = 25°
  • m∠ABD = 2x°
  • m∠CBD = 3x°

Thus:

55 + 2x + 3x + 25 = 180 (triangle sum theorem).

  • Add like terms

80 + 5x = 180

5x = 180 - 80

5x = 100

x = 20

Therefore,

m∠BDC = 180 - (3x + 25) (triangle sum theorem)

  • Plug in the value of x

m∠BDC = 180 - (3(20) + 25)

m∠BDC = 95°

Therefore, applying the triangle sum theorem, the size of ∠BDC = 95°.

Learn more about triangle sum theorem on:

brainly.com/question/7696843

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soldier1979 [14.2K]

<u>Corrected Question</u>

Is the function given by:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right ​

continuous at x=4​? Why or why​ not? Choose the correct answer below.

Answer:

(D) ​Yes, f(x) is continuous at x = 4 because Lim_{x \to 4}f(x)=f(4)

Step-by-step explanation:

Given the function:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right

A function to be continuous  at some value c in its domain if the following condition holds:

  • f(c) exists and is defined.
  • Lim_{x \to c}$ f(x) exists.
  • f(c)=Lim_{x \to c}$ f(x)

At x=4

  • f(4)=\dfrac{1}{4}*4+1=2
  • Lim_{x \to 4}f(x)=2

Therefore: Lim_{x \to 4}f(x)=f(4)=2

By the above, the function satisfies the condition for continuity.

The correct option is D.

3 0
3 years ago
Can someone help me with this please ?
vaieri [72.5K]

Answer:

3.36 cm

Step-by-step explanation:

from the passage before ; the figure of question is similar to the first figure in passage because those triangles have an each equal angle.

Therefore the ratio of side is equal ; 1/0.84=4/x

Solve equation will be x(1)=4(0.84) ; x=3.36 cm

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Step-by-step explanation:

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If we want our ratio to stay the same (3 to 5), we'll need to pair a set of 3 blue tacks with every set of 5 red tacks. In a group of 50, we can make 10 groups of 5 red tacks, so we'll also need 10 groups of 3 blue tacks, which gives us a total of 30 blue tacks

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