Answer:
N/A, but A if anything
Step-by-step explanation:
Let's start with the change within the absolute value.
In f(x), x is turned into x-1. There is no other way to add the -1 into the absolute value.
Therefore, our first transformation is f(x) -> f(x-1). In f(x+C), the graph is moved to the left by c units. Therefore, as C = -1, the graph is shifted to the right by 1 unit.
Next, we can move to the 14. Given that f(x-1) = |x-1|, we can see that we multiply 14 to f(x). Cf(x) vertically stretches a function if C is greater than 0, which 14 is, so the graph is vertically stretched.
After that, we have the negative. This happens outside the absolute values, so it is reflected in -f(x), not f(-x). This reflects a function across the x axis, but all we need to know for this question is that it is reflected.
Finally, we have the +1. This happens outside the absolute values, so it is reflected in f(x) + C, not f(x+C). The value of C moves the graph up by C units, and the +1 therefore moves the graph up by 1 unit.
We thus know 4 things:
1. The graph goes up by 1 units
2. The graph is reflected across the x axis
3. The graph is stretched vertically
4. The graph is shifted to the right by 1 unit
None of the answers given fit these, but A comes the closest.
