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3 years ago

John drove from house to work at an average speed of 30 mph, trip took 40 minutes. How far in meters is his house to work?

Mathematics

1 answer:

AysviL [449]3 years ago

5 0

Answer:

20 meters

Step-by-step explanation:

Firstly we need to know that distance = speed * time

In this particular question, we have the time and the speed, we are only told to find the distance.

Now as we can see, the units are not consistent. While the average speed is 30mph, the time is not in hours but minutes. So practically, we have to convert the time to hours.

Since there are 60 minutes in an hour, the number of hours in 40 minutes would be 40/60 = 2/3 hours.

Now we can proceed to find the distance. We simply multiply the average speed with the time.

Hence, that is 30 * 2/3 = 20 meters

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Answer:

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Step-by-step explanation:

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2 years ago

Find the slope: y=23x+10

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Answer:

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Step-by-step explanation:

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3 years ago

One number is five less than a second number. Three times the first is 14 more than 4 times the second. Find the numbers.

Evgen [1.6K]

Answer:

Second number = -29

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Step-by-step explanation:

Second number = x

First number = x - 5

3*(x-5) = 4x + 14

3x - 3*5 = 4x + 14

3x - 15 = 4x + 14

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2 years ago

A box contains 35 gems, of which 10 are real diamonds and 25 are fake diamonds. Gems are randomly taken out of the box, one at a

USPshnik [31]

Answer:

$Probability = 0.504$

Step-by-step explanation:

Given

$Gems= 35$

$Real = 10$

$Fake = 25$

Required

Determine the probability of selecting two fakes

The probability can be represented as thus: $P(Fake\ and\ Fake)$

Using the following probability formula, we have:

$P(Fake\ and\ Fake) = P(Fake) * P(Fake)$

Each probability is calculated by dividing number of fakes by total number of gems:

$P(Fake\ and\ Fake) = \frac{25}{35} * \frac{25-1}{35-1}$

The minus 1 (-1) represent the numbers of fake and total gems left after the first selection

$P(Fake\ and\ Fake) = \frac{25}{35} * \frac{24}{34}$

$P(Fake\ and\ Fake) = \frac{5}{7} * \frac{12}{17}$

$P(Fake\ and\ Fake) = \frac{60}{119}$

$P(Fake\ and\ Fake) = 0.504$

<em>Hence, the required probability is approximately 0.504</em>

7 0

3 years ago