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You have the correct answer. Nice work. If you need to see the steps, then see below
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First we need to find the midpoint of H and I
The x coordinates of the two points are -4 and 2. They add to -4+2 = -2 and then cut that in half to get -1
Do the same for the y coordinates: 2+4 = 6 which cuts in half to get 3
So the midpoint of H and I is (-1,3). The perpendicular bisector will go through this midpoint
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Now we must find the slope of segment HI
H = (-4,2) = (x1,y1)
I = (2,4) = (x2,y2)
m = (y2 - y1)/(x2 - x1)
m = (4 - 2)/(2 - (-4))
m = (4 - 2)/(2 + 4)
m = 2/6
m = 1/3
Flip the fraction to get 1/3 ---> 3/1 = 3
Then flip the sign: +3 ----> -3
So the slope of the perpendicular bisector is -3
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Use m = -3 which is the slope we found
and (x,y) = (-1,3), which is the midpoint found earlier
to get the following
y = mx+b
3 = -3*(-1)+b
3 = 3+b
3-3 = 3+b-3
0 = b
b = 0
So if m = -3 and b = 0, then y = mx+b turns into y = -3x+0 and it simplifies to y = -3x
So that confirms you have the right answer. I've also used GeoGebra to help confirm the answer (see attached)
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First we need to find the midpoint of H and I
The x coordinates of the two points are -4 and 2. They add to -4+2 = -2 and then cut that in half to get -1
Do the same for the y coordinates: 2+4 = 6 which cuts in half to get 3
So the midpoint of H and I is (-1,3). The perpendicular bisector will go through this midpoint
---------------------
Now we must find the slope of segment HI
H = (-4,2) = (x1,y1)
I = (2,4) = (x2,y2)
m = (y2 - y1)/(x2 - x1)
m = (4 - 2)/(2 - (-4))
m = (4 - 2)/(2 + 4)
m = 2/6
m = 1/3
Flip the fraction to get 1/3 ---> 3/1 = 3
Then flip the sign: +3 ----> -3
So the slope of the perpendicular bisector is -3
-----------------------
Use m = -3 which is the slope we found
and (x,y) = (-1,3), which is the midpoint found earlier
to get the following
y = mx+b
3 = -3*(-1)+b
3 = 3+b
3-3 = 3+b-3
0 = b
b = 0
So if m = -3 and b = 0, then y = mx+b turns into y = -3x+0 and it simplifies to y = -3x
So that confirms you have the right answer. I've also used GeoGebra to help confirm the answer (see attached)
Answer:
Please find the answer in the image attached
Step-by-step explanation:
Here we are asked to solve a pair of linear inequalities.
In order to do so , we are first required to plot the two lines with inequalities taking into considerations.
Hence let us plot
x+2y=-4 and 5x+2y=4
let us first plot x+2y=-4
let us plot a table for the same for two random values of x and putting them into above equation
x y
0 -2
2 -3
Let us now plot these points and join the line .
Let us check whether (0,0) satisfies the in equation or not
0+2(0)≤-4
0≤-4
Which is not true , Hence we shade the portion divided by our line which does not contain (0,0)
Now let us plot the second line 5x+2y=4
let us plot a table for the same for two random values of x and putting them into above equation
x y
0 2
1 -0.5
Let us now plot these points and join the line .
Let us check whether (0,0) satisfies the in equation or not
5(0)+2(0)≤4
0≤4
Which is true , Hence we shade the portion divided by our line which does contain (0,0)
Please refer to the image attached with this answer.
now the commonly shaded area as shown in the image will be our solution to the above pair of in equations.
