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Gelneren [198K]
2 years ago
15

For the dilation with center​ (0,0) shown on the​ graph, your friend says the scale factor is

Mathematics
2 answers:
statuscvo [17]2 years ago
6 0

Answer:

Step-by-step explanation:

From the given figure:

Coordinates of Pre-image triangle ABC are:

A (0, 5), B(-5, 0) and C(5, -5)

and

Coordinate of image triangle A'B'C' are;

A'(0, 2), B'(-2, 0) and C'(2, -2)

The rule of dilation with scale factor k and centered at the origin is given by;

(x,y) ---> (kx,ky)

To find k;

A'(0, 2) = A'(0, 5k)

Comparing both sides we get;

5k = 2

k=2/5

Therefore, the correct scale factor is 2/5

He did mistakes in transformations i.e a huge mistake mathematically.

swat322 years ago
5 0

Answer:

5/7

Step-by-step explanation:

read the graph

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scoundrel [369]

Answer:

6mm

Step-by-step explanation:

7 0
2 years ago
Work out the size of one of the exterior angles
hodyreva [135]

<u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>

⠀

  • A polygon with 10 sides ( Decagon )

⠀

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>

⠀

  • The value of one of the exterior angles

⠀

<u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

\qquad \diamond \:  \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \:  \star

⠀

<u>Solution</u><u> </u><u>:</u><u>-</u>

⠀

Putting the given values, we get,

⠀

\sf \dashrightarrow Exterior ~angle =  \dfrac{360  ^\circ}{10} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \frac{36 \cancel{0}^\circ}{ \cancel{10}} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\  \\

Thus, the value of the exterior angles of a Decagon is 36°.

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\underline{ \rule{227pt}{2pt}} \\  \\

8 0
2 years ago
Read 2 more answers
20 POINTS!
Temka [501]

Answer:

D.The multiplicative identity

Step-by-step explanation:

3/4 x N and which N=1 you multiply them both and should get the same answer

5 0
3 years ago
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What is the degree of the polynomials below <br> 2x^7+4-3x^3+5x^8-4x
Nikolay [14]
The Answer should be 8
7 0
2 years ago
Identify the relation that is also a function. A. {(-1, 1) (0, 0) (1, 1) (2, 4)} B. {(3, 4) (2, 3) (3, 6) (2, 0)} C. {(1, 0) (2,
madreJ [45]

Answer:

Step-by-step explanation:

We are given four sets of relations as

A. {(-1, 1) (0, 0) (1, 1) (2, 4)} \\B. {(3, 4) (2, 3) (3, 6) (2, 0)} \\C. {(1, 0) (2, 3) (3, -2) (1, 6)} \\D. {(3, 2) (3, -2) (3, 6) (3, 8)}

A function is a relation in which every element in the first set has a unique image in the second set.

Let us check this aspect to A.  

This is a function

Now come to B.  3 has two images 4 and 6.  so not a function

Next is C.  in C 1 has two images 0 and 6.  So not a function

For D, 3 has 4 images so not a function.

3 0
3 years ago
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