Answer:
1. C) 2/5 or 4.47 if 2/5 means 2 sqrt(5)
2. sqrt(68)
Step-by-step explanation:
1. using the pythagorean theorem
a^2 + b^2 = c^2
where a = distance AB = 4 b = BC = 2 and c = AC = ?
4^2 + 2^2 = c^2
16 + 4 = c^2
20 = c^2
take the square root of each side
sqrt(20) = c
sqrt(4) * sqrt(5) = c
2sqrt(5) = c
2. using the pythagorean theorem
a^2 + b^2 = c^2
where a = distance AC = 8 b = BC = 2 and c = AB = ?
8^2 + 2^2 = c^2
64 + 4 = c^2
68 = c^2
take the square root of each side
sqrt(68) = c
sqrt(4) * sqrt(17) = c
2sqrt(17) = c
did you forget to put the square root of B
Answer:
See below ~
Step-by-step explanation:
<u>3a : Area of the triangle</u>
- A = 1/2bh
- A = 1/2 x 10 x 8
- A = 5 x 8
- A = <u>40 m²</u>
<u>3b : Area of the semicircle</u>
- Finding the radius (equal to 1/2 of the triangle hypotenuse)
- Apply Pythagorean Theorem here
- √8² + 10² = d
- √64 + 100 = d
- d = √164
- d = 2√41
- r = √41
- A = πr²/2
- A = 3.14 x (√41)² / 2
- A = 1.57 x 41
- A = <u>64.4 m²</u> (nearest tenth)
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