Question

1) Find AC using either the distance formula or the Pythagorean Theorem.

Answer 1

Answer:

1.  C) 2/5 or 4.47   if 2/5 means 2 sqrt(5)

2. sqrt(68)

Step-by-step explanation:

1.  using the pythagorean theorem

a^2 + b^2 = c^2

where a = distance AB = 4   b = BC = 2   and c = AC = ?

4^2 + 2^2 = c^2

16 + 4 = c^2

20 = c^2

take the square root of each side

sqrt(20) = c

sqrt(4) * sqrt(5) = c

2sqrt(5) = c

2.  using the pythagorean theorem

a^2 + b^2 = c^2

where a = distance AC = 8   b = BC = 2   and c = AB = ?

8^2 + 2^2 = c^2

64 + 4 = c^2

68 = c^2

take the square root of each side

sqrt(68) = c

sqrt(4) * sqrt(17) = c

2sqrt(17) = c

did you forget to put the square root of B

Answer 2

Hi There!

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Pythagorean Thereom: $c = \sqrt{a^2 + b^2}$

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Question 1:

a and b = both legs.

c = hypotenuse (AC)

$c = \sqrt{2^2 + 4^2}$

$c = \sqrt{4 + 16}$

$c = \sqrt{20}$

c ≈ 4.47

Answer: C) 2/5 or 4.47

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Question 2:

a and b = both legs.

c = hypotenuse (AB)

$c = \sqrt{2^2 + 8^2}$

$c = \sqrt{4 + 64}$

$c = \sqrt{68}$

c ≈ 8.25

Answer: C) 9 units

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Hope This Helps :)