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kaheart [24]
2 years ago
6

Which function is represented by the graph? f(x) = â’|x â’ 3| 4 f(x) = â’|x 3| 4 f(x) = â’|x â’ 4| 3 f(x) = â’|x 4| 3.

Mathematics
1 answer:
irinina [24]2 years ago
4 0

Functions are used to represent graphs, and vice versa.

The function represented by the graph is f(x) =- |x + 4| + 3

The graph (see attachment) is an absolute value graph.

An absolute value graph is represented as:

f(x) =a |x - h| + k

Where

Vertex = (h,k)

The vertex is the minimum or the maximum point on the graph.

So, we have:

Vertex = (-4,3)

The function becomes

f(x) =a |x + 4| + 3

The function also passes through the point (-1,0).

So, we have:

0 =a |-1 + 4| + 3

0 =a |3| + 3

Remove the absolute bracket

0 =3a + 3

Subtract 3 from both sides

3a =- 3

Divide both sides by 3

a =- 1

Substitute -1 for (a) in f(x) =a |x + 4| + 3

f(x) =- |x + 4| + 3

Hence, the function represented by the graph is f(x) =- |x + 4| + 3

Read more about absolute value graphs at:

brainly.com/question/3381225

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The two dot plots show the number of miles ran by 14 students at the beginning and at the end of the school year compare each me
Naddika [18.5K]

The two dot plots are missing, so i have attached it.

Answer:

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

Step-by-step explanation:

From the attached image, we are told to compare the means for each plot to the nearest tenth.

Mean = Σx/n

Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;

(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133

Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles

Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143

Mean of miles run at the end of the school year = 143/14 = 10.2 miles

Thus;

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

5 0
3 years ago
A camera manufacturer spends $1500 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell f
Reil [10]

Answer:

a)The company has to 250 cameras in one day to equal its daily cost

b)Their daily profit  will be $400

Step-by-step explanation:

Given:

overhead expenses = $1500

labour and materials expenses = $9

cameras sell for $15 each

To Find:

(a)How many cameras must the company sell in one day to equal its daily cost

(b) If the manufacturer can increase production by 50 cameras per day, what would their daily profit be?

Solution:

a) let the number of cameras sold per day be x

Total daily cost = overhead expenses +labour and materials expenses

Total daily cost = 1500 + 9x--------------------------(1)

Total daily revenue = 15x------------------------------(2)

Equating (1) and (2)

1500 + 9x = 15x

1500 = 15x- 9x

1500 = 6x

x= \frac{1500}{6}

x= 250

So, the company has to 250 cameras in one day to equal its daily cost.

b) increasing production by 50 cameras per day will give a daily profit of

=>50 X (17-9)

=>50 X 8

=> 400

5 0
3 years ago
What is the probability of getting a 7 after rolling a single die numbered 1 to 6?
jolli1 [7]
Impossible.
The reason is because there is no way you will get a '7' on a die that is marked 1 - 6. There is no 7.
7 0
4 years ago
Each day, Valerie charges her lunch account for her lunch. If the cost of lunch is $3, then by how much has her lunch account be
Anuta_ua [19.1K]

Answer:

$45

Step-by-step explanation:

$3 times 15 days = $45

6 0
3 years ago
Which is the standard form for this number? (2 x 10) + (5 x 1) + (8 x 1 10,000 )
Veronika [31]
COMBINE LIKE TERMS
2x10+5x+80000x

(2x10)+(5x+80000x)


ANSWER
(2 x 10) + (5 x 1) + (8 x 1 10,000) = 2x10+80005x

4 0
4 years ago
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