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seropon [69]
2 years ago
11

Enter fifty-two million, six hundred thirty-seven thousand, nine hundred fifteen. In number form

Mathematics
2 answers:
insens350 [35]2 years ago
7 0
52,637,915
There
Answer:
expeople1 [14]2 years ago
3 0

Answer:

52,637,915

Step-by-step explanation:

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Which terms in the expression 9d2+15d3+11c2+7 have 14c2 as a like term?
KatRina [158]
That would be the term 11c2 because like 14c2, 11c2 has a constant, a variable and raised to the power of 2.
3 0
3 years ago
According to the norms established for a reading comprehension test, eighth-graders should average 83.2 with a standard deviatio
joja [24]

Answer:

t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73    

p_v =P(t_{44}>2.73)=0.0045    

If we compare the p value and a significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

Step-by-step explanation:

Data given and notation    

\bar X=86.7 represent the average life for the sample    

s=8.6 represent the population standard deviation    

n=45 sample size    

\mu_o =83.2 represent the value that we want to test    

\alpha=0.01 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed  test.  

What are H0 and Ha for this study?    

Null hypothesis:  \mu \leq 83.2  

Alternative hypothesis :\mu > 83.2  

Compute the test statistic  

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73    

Give the appropriate conclusion for the test  

First we need to calculate the degrees of freedom given by:

df=n-1=45-1=44

Since is a one side right tailed test the p value would be:    

p_v =P(t_{44}>2.73)=0.0045    

Conclusion    

If we compare the p value and a significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

8 0
3 years ago
Help no idea what to do
malfutka [58]
The first cube is 12, the second one is 10. Just do length times width times height.
3 0
3 years ago
Read 2 more answers
Two more than a certain number is 15 less than twice the number. Find the number
Svetllana [295]
2+x=2x-15
>> 2+15=2x-x
>> 17 = x

So the answer is <u>17</u>
6 0
3 years ago
Read 2 more answers
20,18,13,17,18 find the mean,median and mode​
Degger [83]
<h3>Answer:</h3>

Mean: 17.2

Median: 18

Mode: 18

<h3>Solution:</h3>

Mean: The sum of all observation divided by several observation

  • 20+18+13+17+18=86
  • 86÷5=
  • 17.2

Median:it is the middlemost observation of data arraged in increasing or decreasing order of values

  • (13,17,18,18,20)
  • (17,18,18)
  • (18)

Mode:it is the value that occurs frequently in a set of data

  • (13 , 17 , 18 , 18 , 20)

Hope it helps

6 0
2 years ago
Read 2 more answers
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