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seropon [69]
2 years ago
11

Enter fifty-two million, six hundred thirty-seven thousand, nine hundred fifteen. In number form

Mathematics
2 answers:
insens350 [35]2 years ago
7 0
52,637,915
There
Answer:
expeople1 [14]2 years ago
3 0

Answer:

52,637,915

Step-by-step explanation:

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A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls invol
Andre45 [30]

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b

Step-by-step explanation:

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Yo soy muy grande cojones y muy grande Pena!!!!!!
7 0
3 years ago
In 2000, the total population of the U.S. was 281.4 million people. In 2010, it was 308.7 million people. What is the average ra
kifflom [539]

Answer:

2.73 million people per year

Step-by-step explanation:

Turn sentences into coordinates/points:

In 2000, 281.4 million people

  • (x₁, y₁) = (2000, 281.4)

In 2010, 308.7 million people

  • (x₂, y₂) = (2010, 308.7)

Rate of population per year:

\sf \dfrac{y_2 - y_1}{x_2- x_1} \ \  where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points

\rightarrow \sf \dfrac{308.7-281.4}{2010-2000}

\rightarrow \sf 2.73 \ million \ people

5 0
2 years ago
An introductory psychology class with n=44 students has 9 freshman males, 15 freshman females, 8 sophomore males, and 12 sophomo
andrezito [222]

Answer:

0.61

Step-by-step explanation:

Pr (female) =  total number of females(n')/Total number of students(n)

Where P(female) = probability of selectinga female

Pr(female) = n'/n................. Equation 1

Given: n = 44 students, n' = 15+12 = 27 females

Substitute into equation 1

Pr(female) = 27/44

Pr(female) = 0.61.

Hence the probability of selecting a female is 0.61

3 0
3 years ago
It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 55, \pi = \frac{24}{55} = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - \frac{0.07}{2} = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0
3 years ago
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