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4 years ago

HELLPP ASAP!!!! 1. Find the unknown side lengths in these right triangles.

Mathematics

2 answers:

lakkis [162]4 years ago

8 0

Answer:

Step-by-step explanation:

5x2

GalinKa [24]4 years ago

8 0

Okay so for the first one use the pythagorean theorem. 5^2 x 2^2 so simplify that rq. 25 x 4. so now solve that and c=100 which we need to get the square root of. so that would be 10 so c=10

then for the next one the square root of 8 squared is just 8 and 4^2 is 16. so now the equation for that is 8 +y^2= 16 so simplify that and the solution for that is 2√2

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What happens when a figure is dilated .

zaharov [31]

Answer:

A dilation is a transformation that produces an image that is the same shape as the original, but is a different size. A dilation that creates a larger image is called an enlargement. A dilation that creates a smaller image is called a reduction. A dilation stretches or shrinks the original figure.

7 0

3 years ago

Someone help me ASAP!!!

Mila [183]

Given : Anne buys 600 packets of mints.

Given : Of these 600 packets of mints, 34% are small packets and 40% are large packets.

$:\implies$ Total % of small and large packets is (34 + 40) = 74%

It means : The remaining percentage is of the medium packets of mints which were brought by Anne.

$:\implies$ % of medium packets brought by Anne : (100 - 74) = 26%

$:\implies \textsf{Number of medium packets brought by Anne : $\left(\dfrac{26}{100} \times 600\right)$}$

$:\implies \textsf{Number of medium packets brought by Anne : $\left(26 \times 6\right)$ = 156}$

Given : Ben buys 400 packets of mints.

$\textsf{Given : Of these 400 packets of mints, $\dfrac{3}{10}$ are small and $\dfrac{1}{10}$ are large}$

$\implies \textsf{Total fraction of small and large packets brought by Ben :$\left(\dfrac{3}{10} + \dfrac{1}{10}\right)$}$

It means : The remaining fraction is of the medium packets of mints which were brought by Ben.

$\implies \textsf{Fraction of medium packets brought by Ben : $\left(1 - \dfrac{3}{10} - \dfrac{1}{10}\right)$}$

$\implies \textsf{Fraction of medium packets brought by Ben : $\left(1 - \dfrac{4}{10}\right)$ = $\dfrac{6}{10}$}$

$:\implies \textsf{Number of medium packets brought by Ben : $\left(\dfrac{6}{10} \times 400\right)$}$

$:\implies \textsf{Number of medium packets brought by Anne : $\left(6 \times 40\right)$ = 240}$

Given : Chas buys 210 small packets of mints.

Given : Number of small packets : number of medium packets = 3 : 4

$\implies \mathsf{\dfrac{210}{number \ of \ medium \ packets} = \dfrac{3}{4}}$

$\implies \mathsf{Number \ of \ medium \ packets = \left(210 \times \dfrac{4}{3}\right)}$

$\implies \textsf{Number of medium packets brought by Chas = 280}$

Total number of medium packets of mints brought by these three shop keepers (Anne, Ben, Chas) are :

$:\implies$ (156 + 240 + 280)

$:\implies$ 676

5 0

3 years ago

F(x) = -4x2 + 6x - 4 Find f(5)

Anni [7]

Answer:

f(5) = -74

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = -4x² + 6x - 4

f(5) is x = 5

Step 2: Evaluate

Substitute: f(5) = -4(5)² + 6(5) - 4
Exponents: f(5) = -4(25) + 6(5) - 4
Multiply: f(5) = -100 + 30 - 4
Add: f(5) = -70 - 4
Subtract: f(5) = -74

3 0

3 years ago

Find the inverse of the function. f(x) = 6x3 + 3

ahrayia [7]

The answer is    $f^{-1}(x) = \sqrt[3]{ \frac{x-3}{6}}$

Our function is f(x) = 6x³ + 3. We need to find f⁻¹(x)
Step 1: Substitute y for f(x):
y = 6x³ + 3
Step 2: Switch x and y because every (x, y) has its partner (y, x):
x = 6y³ + 3
Step 3: Solve for y:
   $6y^{3} =x-3 \\ 
y^{3}= \frac{x-3}{6} \\ 
y = \sqrt[3]{ \frac{x-3}{6}}$
   $f^{-1}(x) = \sqrt[3]{ \frac{x-3}{6}}$

6 0

4 years ago

1) Write an equation for the line.

ValentinkaMS [17]

Answer:

1) y = (-13/6)x + (37/3)

2) -⅔

3) negative

Step-by-step explanation:

1) slope = (1.5-8)/(5-2) = -13/6

y = (-13/6)x + c

x = 2, y = 8

8 = (-13/6)(2) + c

c = 37/3

y = (-13/6)(6) + (37/3) = -⅔

2) y = (-13/6)x + (37/3)

3) since the slope is negative, the association between the variables is negative

4 0

4 years ago