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2 years ago

OMG HELP RN

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

4 0

Answer:

C would be the answer

Hope this helps!

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What is -63 divided by 7

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Answer:

-9

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The sum of a number and twenty is greater than four times the number decreased by one

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is that the question?

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2 years ago

2(5-8x-9x)+4(7x+7)=14

xenn [34]

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if you are solving for X' it is X=4

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2 years ago

A craft store buys 50 yards of satin ribon for $12.50. The store sells the ribbon by the foot. A customer can purchase 5 feet of

amm1812

Answer:

$8.1

Step-by-step explanation:

Convert 45 yards of ribbon to feet through proper conversion factor.

(45 yards)(3 ft / 1 yard) = 135 feet

Divide this number by 5 to determine the number of 5-ft ribbon that customers can purchased.

n = 135 ft / 5 ft = 27

Then, multiply by $0.80.

R = (27)($0.80) = $21.6

The profit is equal to $21.6 and $13.50,

P = $21.6 - $13.50 = $8.1

Answer: $8.1

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3 years ago

Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

Solution :- 

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in Geometric Progression where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

2 years ago