Khalil uses the method of similar triangles to find the distance across the river,
- The distance across the river is
Reasons:
The distances between the formed the sight-lines are;
= 185 feet
= 275 feet
The distance between the point close to the river and the next point further from the river = 150 feet
In triangles ΔPRB and ΔPOC, we have;
∠PRE = ∠POC = 90° Given
∠PER ≅ ∠PCO By corresponding angle formed between two parallel lines and a common transversal.
∴ ΔPRE is similar to ΔPOC by Angle-Angle, AA, similarity theorem
Which gives;
Let <em>x</em> represent the distance across the river, we have;
= x
= 150 + x
Which gives;
275·x = 185 × (150 + x) = 27,750 + 185·x
275·x - 185·x = 27,750
90·x = 27,750
Therefore, the distance across the river, x = =
Learn more about similar triangles here
brainly.com/question/10703692