Answer:
-4.03846153846
Step-by-step explanation:
done
Let , coordinate of points are P( h,k ).
Also , k = 3h + 1
Distance of P from origin :
Distance of P from ( -3, 4 ) :
Now , these distance are equal :
Solving above equation , we get :
Hence , this is the required solution.
This is a geometric sequence.
a = 15625,
Common ratio = 6250/15625 = 2500/6250 = 0.4
an for GP = ar^(n - 1)
= 15625*(0.4)^(n - 1)
Answer:
20
Step-by-step explanation:
nPr = n!/(n-r)!
5P2 = 5!/(5-2)!
= 5!/3!
= 5×4×3!/3!
= 5×4
= 20
A good way of doing this problem would be to use cross multiplication of ratios
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Then cross multiply
(10 girls)(270 students)=(X girls)(18 students)
2700=18x
150=x