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EastWind [94]
2 years ago
15

How do I factor this problem?

Mathematics
2 answers:
Vladimir [108]2 years ago
8 0

Answer:

7x(4x-1)

Step-by-step explanation:

First, find the largest integer that divides evenly into both numbers. In this case, 28 and 7 are both divisible by 7.

Next, find the highest degree of the variable that divides evenly into both. Here, that's just x. I'll show another example of that below.

Multiply those together, and you get 7x. That is what we need to factor out. Divide by that factor while multiplying by that factor at the same time to keep the value of the expression equal:

28x^2-7x\\\\7x(\frac{28x^2}{7x}-\frac{7x}{7x})\\\\7x(4x-1)

Another example of what I said above would be this:

Take 4x + 2. The largest integer that divides these is 2, and the highest degree of x that divides them is 0. That is an x⁰, and that is equal to 1. Multiply those, and you just get 2.

4x+2\\\\2(\frac{4x}{2}+\frac{2}{2})\\\\2(2x+1)

STALIN [3.7K]2 years ago
4 0
Answer = 7x(4x-1) . Hope it helps.
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Step-by-step explanation:

15/100 ?/60

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8/5÷3=______<br>Answer in a fraction form <br><br>PLZ HELP ME​
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Nadusha1986 [10]

The value of the variable x will be 37°. Then the measure of the angle ∠QNP will be 105°.

<h3>What is an angle?</h3>

The angle is the distance between the intersecting lines or surfaces. The angle is also expressed in degrees. The angle is 360 degrees for one complete spin.

Supplementary angle - Two angles are said to be supplementary angles if their sum is 180 degrees.

The measure of angles ∠MNQ = (2x + 1)° and ∠QNP = (3x - 6)°.

Then the value of x will be

We know that the angles ∠MNQ and ∠QNP are supplementary angles. Then the value of the variable x will be

∠MNQ + ∠QNP = 180°

(2x + 1)° + (3x - 6)° = 180°

5x - 5° = 180°

5x = 185°

x = 37°

Then the measure of the angle ∠QNP will be

∠QNP = [3(37) - 6]°

∠QNP = 111° - 6°

∠QNP = 105°

The value of the variable x will be 37°. Then the measure of the angle ∠QNP will be 105°.

More about the angled link is given below.

brainly.com/question/15767203

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4 0
2 years ago
Write the Slope-Intercept and Point-Slope forms of the line passing through the point (-3, 2) and having a slope of -4/5
weeeeeb [17]

Answer:

slope-intercept: y=\frac{-4}{5} x-\frac{2}{5}

point-slope: y-2=\frac{-4}{5} (x+3)

Step-by-step explanation:

The slope-intercept form of a line is written as y = mx + b, where m is the slope and b is the y-intercept.

The point-slope form of a line is written as y - y1 = m(x - x1), where (x1, y1) is a given point and m is the slope.

Here, we see that the slope is -4/5, which means that m = -4/5. Since we're given a point (-3, 2), let's go ahead and just write the point-slope form already. (x1, y1) = (-3, 2) so x1 = -3 and y1 = 2. Then:

y - y1 = m(x - x1)

y - 2 = (-4/5) * (x + 3)

y-2=\frac{-4}{5} (x+3)

Now, we want to find the slope-intercept form, so we need to figure out the y-intercept. Well, first, let's plug in what we know:

y = mx + b

y = (-4/5)x + b

Any point on this line will satisfy the above equation. Since (-3, 2) is on this line, if we plug -3 in for x and 2 in for y, the equation should hold true, so we can solve for b:

y = (-4/5)x + b

2 = (-4/5) * (-3) + b

2 = 12/5 + b

b = -2/5

So, the y-intercept is -2/5. Then the slope-intercept form is:

y=\frac{-4}{5} x-\frac{2}{5}

Thus, our two equations are:

slope-intercept: y=\frac{-4}{5} x-\frac{2}{5}

point-slope: y-2=\frac{-4}{5} (x+3)

8 0
3 years ago
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